Home >Common Problem >How to find the name attribute in jquery

How to find the name attribute in jquery

尊渡假赌尊渡假赌尊渡假赌
尊渡假赌尊渡假赌尊渡假赌Original
2023-05-29 10:59:173144browse

The methods for jquery to find the name attribute are: 1. "$("Element[name='name")" directly matches the element with the name attribute of the specified name; 2. "$("Element[name!= 'Name")" matches all name attributes except the specified name; 3. "$("Element[name^='name")" matches all name attributes starting with the specified name; 4. "$("Element[ name$='name")" matches all name attributes ending with the specified name.

How to find the name attribute in jquery

Operating system for this tutorial: Windows 10 system, jQuery3.6.0 version, Dell G3 computer.

The methods for jquery to find the name attribute are:

1. Directly match all input elements whose name attribute is a newsletter

<input type="checkbox" name="newsletter" value="Hot Fuzz" />
<input type="checkbox" name="newsletter" value="Cold Fusion" />
<input type="checkbox" name="accept" value="Evil Plans" />jquery代码:$("input[name=&#39;newsletter&#39;]")

2. Match all input elements whose name attribute is not newsletter

<input type="checkbox" name="newsletter" value="Hot Fuzz" />
<input type="checkbox" name="newsletter" value="Cold Fusion" />
<input type="checkbox" name="accept" value="Evil Plans" />jquery代码:$("input[name!=&#39;newsletter&#39;]")

3. Match all input elements whose name starts with 'news'

<input name="newsletter" />
<input name="milkman" />
<input name="newsboy" />jquery代码:$("input[name^=&#39;news&#39;]")  //name属性值以news开头的input元素

4. Match all input elements whose name starts with 'letter' 'Input element at the end

<input name="newsletter" />
<input name="milkman" />
<input name="jobletter" />jquery代码:$("input[name$=&#39;letter&#39;]")

The above is the detailed content of How to find the name attribute in jquery. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn