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How to set default value using defaultdict in Python?

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2023-04-26 17:07:091314browse

Preface

When searching for a certain value in the dictionary, if the key does not exist, a keyerror error will be returned instead of a default value. If you want to return a default value, you can use defaultdictFunction. Defaultdict is a subclass of Python's built-in dict class. It has the same function as dict, but it has a default value. If the key value does not exist, it returns a default value.

Syntax

dict =defaultdict( factory_function)

defaultdict can accept a factory function as a parameter, where factory_function can be list, set, str, etc., the function When ket does not exist, the default value of a factory function is returned. For example, list corresponds to [], str corresponds to the empty string, set corresponds to set(), and int corresponds to 0.

Normal use of dict is as follows:

l=['A','B','C','D']
di={}

for i in l:
    print(i) # 'A
    di[i]+=1 # KeyError: 'A'

print(di)

Use defaultdict()

from collections import defaultdict
dict1 = defaultdict(int)
dict2 = defaultdict(set)
dict3 = defaultdict(str)
dict4 = defaultdict(list)
dict4[1] = 666
dict4[2] = 888
print(dict1[0]) # 0
print(dict2[0]) # set()
print(dict3[0]) # 
print(dict4[0]) # []
print(dict4[1]) # 666
print("*" * 30)
print(dict1) # defaultdict(<class &#39;int&#39;>, {0: 0})
print(dict2) # defaultdict(<class &#39;set&#39;>, {0: set()})
print(dict3) # defaultdict(<class &#39;str&#39;>, {0: &#39;&#39;})
print(dict4) # defaultdict(<class &#39;list&#39;>, {1: 666, 2: 888, 0: []})

The difference between setdefault() and defaultdict()

The dict.setdefault() method has two parameters, the first is the parameter and the second is the default value

lst = [&#39;A&#39;, &#39;B&#39;, &#39;C&#39;, &#39;D&#39;, &#39;e&#39;]
dic = {}
 
for i in lst:
    dic.setdefault(i, 0)
    dic[i] += 1
print(dic)# {&#39;A&#39;: 1, &#39;B&#39;: 1, &#39;C&#39;: 1, &#39;D&#39;: 1, &#39;e&#39;: 1}

setdefault()

setdefault() is an instance method of the dictionary, receiving two parameters. Its usage is similar to the get() method of the dictionary, but it is more powerful than the get() method. Both set a default value for the dictionary key.

The difference between the two is: the default value set by the get method will not change the original dictionary, while the default value set by setdefault will change the value of the original dictionary.

Note: When using dict[key]=value, an error will be reported if the key does not exist; when using dict.get(key), if the key does not exist, a default value will be returned.

dic1 = {"A": "a", "B": "b"}
x = dic1.get("E", "e")
print(x) # e
print(dic1) # {&#39;A&#39;: &#39;a&#39;, &#39;B&#39;: &#39;b&#39;}
 
dic2 = {"C": "c", "D": "d"}
y = dic2.setdefault("E", &#39;e&#39;)
print(y) # e
print(dic2) # {&#39;C&#39;: &#39;c&#39;, &#39;D&#39;: &#39;d&#39;, &#39;E&#39;: &#39;e&#39;}

defaultdict()

defaultdict is a factory function under the collections module. It is used to construct dictionary objects and receives a function (callable) object as a parameter. What is the type returned by the parameter, and what type is the value corresponding to the key.

from collections import defaultdict
 
lst = [("A", "1"), ("B", "1"), ("A", "2"), ("B", "2"), ("A", "3"), ("B", "3")]
dic = defaultdict(list)
print(dic)
for key, value in lst:
    dic[key].append(value)
print(dic)
print(type(dic))
for key, value in dic.items():
    print(key, value)

How to set default value using defaultdict in Python?

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