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What is the method to determine leap year in javascript?
- 王林Original
- 2021-11-03 17:01:557965browse
How to determine leap year in javascript: [var year=Number(prompt("Please enter a year")); var isRun=year@0==0&&year 0!=0||year@0= =0; console.lo...].
#The operating environment of this article: windows10 system, javascript 1.8.5, thinkpad t480 computer.
Determining leap years in ordinary years is a problem often encountered in the process of learning programming. Everyone has encountered this problem when they were in school. I believe everyone has a way to solve this problem.
So if you are asked to use javascript language, how to solve this problem?
Specific code:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>判断闰年</title>
</head>
<body>
<script>
//判断润年：
//(year%4==0&&year%100 != 0) ||(year%400==0);
var year=Number(prompt("请输入一个年份"));
var isRun=year%400==0&&year%100!=0||year%400==0;
console.log(year+"是如年吗？"+isRun);
/*1.能被4整除，但不能被100整除
或
1.1年份能被4整除
同时满足
1.2不能被100整除
2.能被400整除
*
* 1.var year=2016;
* 1.1能不能被4整除
* year%4==0;
* 结果为真：则能被4整除
* 结果为假：则不能被4整除
*
* 1.2不能被100整除
* 结果为真：则不能被100整除
* 结果为假：则能被100整除
*
* 1.3能被400整除
* year%400==0
* 结果为真：则能被400整出
* 结果为假：则不能被400整除
* */
</script>
</body>
</html>Recommended learning: javascript video tutorial
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