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Python program to determine leap year: A leap year is a hundred years that is divisible by 400, a leap year is a hundred years that is not divisible by 4, the code is [if (year % 400) == 0&&if (year % 4) = = 0].
The operating environment of this tutorial: Windows 7 system, python version 3.9, DELL G3 computer.
Python program to determine leap year:
The following example is used to determine whether the year entered by the user is a leap year:
Example
# -*- coding: UTF-8 -*- # Filename : test.py # author by : www.runoob.com year = int(input("输入一个年份: ")) if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print("{0} 是闰年".format(year)) # 整百年能被400整除的是闰年 else: print("{0} 不是闰年".format(year)) else: print("{0} 是闰年".format(year)) # 非整百年能被4整除的为闰年 else: print("{0} 不是闰年".format(year))
We can also use embedded if statements to achieve:
The output result of executing the above code is:
输入一个年份: 2000 2000 是闰年
输入一个年份: 2011 2011 不是闰年
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