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HomeBackend DevelopmentGolangHow to find the absolute value in Go language

How to find the absolute value in Go language

Jun 04, 2021 pm 03:38 PM
go languageabsolute value

In the Go language, you can use the abs() function in the math package to find the absolute value. The syntax format "math.Abs(x)" can return the absolute value of the parameter x; abs() function input The output value types are all "float64".

How to find the absolute value in Go language

The operating environment of this tutorial: Windows 10 system, GO 1.11.2, Dell G3 computer.

In the go language, you can use the abs() function in the math package to find the absolute value.

Syntax:

math.Abs(x float64)

Return value:

  • Abs returns the absolute value of x.

Special cases are:

Abs(±Inf) = +Inf
Abs(NaN) = NaN

Example

package main 

import (
    "fmt"
    "math"
)
func main() {
    x := math.Abs(-2)
    fmt.Printf("%.1f\n", x)
    y := math.Abs(2)
    fmt.Printf("%.1f\n", y)
}

Extended information:

Golang Some commonly used methods under the math package

package main

import (
    "fmt"
    "math"

)
func main() {
    i := 1
    fmt.Println(math.Abs(float64(i)))         //取到绝对值
    fmt.Println(math.Ceil(3.8))             //向上取整
    fmt.Println(math.Floor(3.6))             //向下取整
    fmt.Println(math.Mod(11,3))         //取余数 11%3 效果一样
    fmt.Println(math.Modf(3.22))             //取整数跟小数
    fmt.Println(math.Pow(3,2))             //X 的 Y次方  乘方
    fmt.Println(math.Pow10(3))             //10的N次方 乘方
    fmt.Println(math.Sqrt(9))             //开平方  3
    fmt.Println(math.Cbrt(8))             //开立方  2
    fmt.Println(math.Pi)                     //π
    fmt.Println(math.Round(4.2))          //四舍五入

    fmt.Println(math.IsNaN(3.4))           //false   报告f是否表示一个NaN(Not A Number)值。
    fmt.Println(math.Trunc(1.999999))      //1    返回整数部分(的浮点值)。
    fmt.Println(math.Max(-1.3, 0))     //0   返回x和y中最大值
    fmt.Println(math.Min(-1.3, 0))    //-1.3  返回x和y中最小值
    fmt.Println(math.Dim(-12, -19))   //7 函数返回x-y和0中的最大值
    fmt.Println(math.Dim(-12, 19))    //0 函数返回x-y和0中的最大值
    fmt.Println(math.Cbrt(8))             //2  返回x的三次方根
    fmt.Println(math.Hypot(3, 4))     //5  返回Sqrt(p*p + q*q)
    fmt.Println(math.Pow(2, 8))       //256  返回x^y

}

Result

1
4
3
2
3 0.2200000000000002
9
1000
3
2
3.141592653589793
4
false
1
0
-1.3
7
0
2
5
256

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