The solution for jquery to obtain garbled url parameters: 1. Use regular analysis method, the code is [function getQueryString(name)]; 2. Get the string after the [?] character in the url, the code is [ var url = location.search;].
The operating environment of this tutorial: windows7 system, jquery1.12 version, DELL G3 computer.
Recommendation: jquery video tutorial
Solution to jquery getting url parameter garbled:
Method 1 : Regular analysis method
The code is as follows:
function getQueryString(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); var r = window.location.search.substr(1).match(reg); if (r != null) return unescape(r[2]); return null; }
Called like this:
The code is as follows:
alert(GetQueryString("参数名1")); alert(GetQueryString("参数名2")); alert(GetQueryString("参数名3"));
Method 2:
The code is as follows:
<span style="font-size: 16px;"><Script language="javascript"> function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) { theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); } } return theRequest; } </Script></span>
1. Call like this:
The code is as follows:
<Script language="javascript"> var Request = new Object(); Request = GetRequest(); var 参数1,参数2,参数3,参数N; 参数1 = Request['参数1']; 参数2 = Request['参数2']; 参数3 = Request['参数3']; 参数N = Request['参数N']; </Script>
If the parameters contain Chinese characters, pay attention to the encoding and decoding :
The code is as follows:
<span style="font-size:18px;">1.传参页面 Javascript代码:<script type=”text/javascript”> function send(){ var url = "test01.html"; var userName = $("#userName").html(); window.open(encodeURI(url + "?userName=" + userName)); } </script>
2. Receive parameter page: test02.html
<script> var urlinfo = window.location.href;//获取url var userName = urlinfo.split(“?”)[1].split(“=”)[1];//拆分url得到”=”后面的参数 $(“#userName”).html(decodeURI(userName)); </script></span>
Related free learning recommendations: javascript (video )
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