How many bytes does java char occupy?

In java, char occupies 2 bytes. In Java, as long as it is a character, whether it is a number, English or Chinese character, it takes up two bytes. Reason: Java compiler uses Unicode encoding by default, so 2 bytes can represent all characters.

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1: "Byte" is byte, "Bit" is bit;

2: 1 byte = 8 bit;

char is 2 bytes in java. Java uses Unicode, 2 bytes (16 bits) to represent a character.

The example code is as follows:

public class Test {
 
 
	public static void main(String[] args) {
		String str= "中";
		char x ='中';
		byte[] bytes=null;
		byte[] bytes1=null;
		try {
			bytes = str.getBytes("utf-8");
			bytes1 = charToByte(x);
		} catch (UnsupportedEncodingException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		System.out.println("bytes 大小："+bytes.length);
		System.out.println("bytes1大小："+bytes1.length);
	}
	public static byte[] charToByte(char c) { 
        byte[] b = new byte[2]; 
        b[0] = (byte) ((c & 0xFF00) >> 8); 
        b[1] = (byte) (c & 0xFF); 
        return b; 
    }
}

Running result:

bytes 大小：3
bytes1大小：2

Java uses unicode to represent characters. The unicode of the Chinese character "中" is 2 bytes.

The String.getBytes(encoding) method is to obtain the byte array representation of the specified encoding.

Usually gbk/gb2312 is 2 bytes and utf-8 is 3 bytes.

If encoding is not specified, the system default encoding will be used.

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