Share 9 interview questions about JavaScript Promises

Please complete the following 9 questions

1. Multiple<span style="font-size: 18px;">.catch</span>

var p = new Promise((resolve, reject) => {
  reject(Error('The Fails!'))
})
p.catch(error => console.log(error.message))
p.catch(error => console.log(error.message))

What will be the output of the above code? Please choose the correct answer:

• [ ] Print the message once
• [x] Print the message twice
• [ ] UnhandledPromiseRejectionWarning
• [ ] Program exit

Analysis:

We use the constructor method to create a Promise and pass the reject callback The error is triggered immediately.

Then .catch works similar to DOM's .addEventListener(event, callback) or Event Emitter's .on(event, callback), where can add multiple callbacks. Each is called with the same parameters.

2. Multiple .catch##

var p = new Promise((resolve, reject) => {
  return Promise.reject(Error('The Fails!'))
})
p.catch(error => console.log(error.message))
p.catch(error => console.log(error.message))

The output of the above code will be What? Please choose the correct answer:

[ ] Print the message once
• [ ] Print the message twice
• [x]
• UnhandledPromiseRejectionWarning
[ ] Program exit

Analysis:

When using the Promise constructor, you must call

resolve() or reject() callback. The Promise constructor does not use your return value, so no other Promises created by Promise.reject() will actually be received.

When there is no

.catch after Promise.reject(), the answer is UnhandledPromiseRejectionWarning.

3. Link .then and .catch

var p = new Promise((resolve, reject) => {
    reject(Error('The Fails!'))
  })
  .catch(error => console.log(error))
  .then(error => console.log(error))

What will be the output of the above code? Please choose the correct answer:

[x] prints an error and
• undefined
[ ] prints twice an error
• [ ]
• UnhandledPromiseRejectionWarning
[ ]
• undefined

Parsing

When chaining

.then and .catch, it's helpful to think of them as a series of steps. Each .then receives as its argument the value returned by the previous .then. However, if your "step" encounters an error, any subsequent .then "steps" will be skipped until .catch is encountered. If you want to override an error, all you have to do is return a non-error value. Can be accessed via any subsequent .then.

Tip: console.log() always returns undefined.

4. Link.catch##

var p = new Promise((resolve, reject) => {
    reject(Error('The Fails!'))
  })
  .catch(error => console.log(error.message))
  .catch(error => console.log(error.message))

What will be the output of the above code? ? Please choose the correct answer:

[x] Print the error message once

• [ ] Print the error message twice
• [ ] UnhandledPromiseRejectionWarning
• [ ] Program exit

Parsing

When chaining

.catch

, each only processes the previous .then or `.catch Error raised in "step". In this example, the first .catch returns console.log, which can only be achieved by adding .then() after the two .catch Come visit.

5. Multiple .catch##

new Promise((resolve, reject) => {
    resolve('Success!')
  })
  .then(() => {
    throw Error('Oh noes!')
  })
  .catch(error => {
    return "actually, that worked"
  })
  .catch(error => console.log(error.message))

The output of the above code will be What? Please choose the correct answer:

[ ] Print the message once

[ ] Print the message twice
• [ ] UnhandledPromiseRejectionWarning
• [x] Print nothing
• Parsing

Tip:

.catch can be done simply by returning a regular value to ignore (or override) errors. This trick only works when subsequent .then

receives the value.

6. The process between

.then

Promise.resolve('Success!')
  .then(data => {
    return data.toUpperCase()
  })
  .then(data => {
    console.log(data)
  })

The output of the above code will What will it be? Please choose the correct answer:

[ ] print "Success!" and "SUCCESS!"

[ ] print "Success!"
• [x] print "SUCCESS!"
• [ ] Does not print anything
• Parsing

Tips: .then passes the data in sequence, starting from return value

to the next

.then(value => /* handle value */). In order to pass the value to the next .then

,

return is the key.

7. The process between

.then

Promise.resolve('Success!')
  .then(data => {
    return data.toUpperCase()
  })
  .then(data => {
    console.log(data)
    return data
  })
  .then(console.log)

The output of the above code will What will it be? Please choose the correct answer:

• [ ] 打印 "SUCCESS!"
• [ ] 打印 "Success!"
• [x] 打印 "SUCCESS!" 和 "SUCCESS!"
• [ ] 不打印任何内容

解析：

有两个 console.log 调用将被调用。

8. .then 之间的流程

Promise.resolve('Success!')
  .then(data => {
    data.toUpperCase()
  })
  .then(data => {
    console.log(data)
  })

以上代码的输出将会是什么？请选择正确的答案：

• [ ] 打印 "SUCCESS!"
• [ ] 打印 "Success!"
• [ ] 打印 "SUCCESS!" 和 "SUCCESS!"
• [x] 打印 undefined

解析：

提示：.then 依次传递数据，从返回值到下一个  .then(value => /* handle value */)。

为了将值传递给下一个 .then，return 是关键。

9. .then 和 .catch 之间的流程

Promise.resolve('Success!')
  .then(() => {
    throw Error('Oh noes!')
  })
  .catch(error => {
    return 'actually, that worked'
  })
  .then(data => {
    throw Error('The fails!')
  })
  .catch(error => console.log(error.message))

以上代码的输出将会是什么？请选择正确的答案：

• [ ] 打印 "Oh noes!" 和 "The fails!"
• [ ] 打印 "Oh noes!"”
• [x] 打印 "The fails!"
• [ ] 打印 "actually, that worked"
• [ ] 不打印任何内容

解析：

本文转载自：https://segmentfault.com/a/1190000021255822

英文原文地址： https://danlevy.net/javascript-promises-quiz/

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