='a' && cl<='z'){printf("lowercase");}". ​Character data is stored in ASCII code. The lowercase letters a to z are from 97 to 122 in the ASCII code table, so as long as the variable cl is greater than a and less than z, it can be guaranteed to be lowercase letters."/> ='a' && cl<='z'){printf("lowercase");}". ​Character data is stored in ASCII code. The lowercase letters a to z are from 97 to 122 in the ASCII code table, so as long as the variable cl is greater than a and less than z, it can be guaranteed to be lowercase letters.">

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What is the correct expression to determine whether the char variable cl is a lowercase letter?

烟雨青岚
烟雨青岚Original
2020-06-22 15:24:1111969browse

The correct expression is "if(cl >='a' && cl<='z'){printf("lowercase");}". Character data is stored in ASCII code. The lowercase letters a to z are from 97 to 122 in the ASCII code table, so as long as the variable cl is greater than a and less than z, it can be guaranteed to be lowercase letters.

What is the correct expression to determine whether the char variable cl is a lowercase letter?

What is the correct expression to determine whether the char variable cl is a lowercase letter?

The correct expression to determine whether the char type variable cl is a lowercase letter is

if(cl >=&#39;a&#39; && cl<=&#39;z&#39;)
{
printf("小写");
}

Character data is stored in ASCII code internally in the computer. English uppercase letters and Lowercase letters are consecutive in the ASCII code table. The lowercase letters a to z are from 97 to 122, so as long as the variable cl is greater than a and less than z, it is guaranteed to be a lowercase letter.

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