How to output three numbers according to size in C language?

Analysis and implementation of outputting three numbers by size in C language:

1. Analysis: The sorting of three numbers only requires three comparisons.

First, let these three numbers be a, b, and c respectively.

(1) Compare a with b, if a > b, exchange the values ​​​​of a and b, compare a with c,

(2) If a > c, exchange a and c Compare the value b with c,

(3) If b > c, exchange the values ​​​​of b and c

After three rounds of comparison, output a, b, c in order of size arranged.

2. Implementation:

#include <stdio.h>
int main()
{
    int a;
    int b;
    int c;
    int t; // 临时变量用于交换两变量的值
    printf("请输入a、b、c的值，中间用空格隔开：");
    scanf("%d%d%d", &a, &b, &c);
    if (a > b) {
        t = a;
        a = b;
        b = t;
    }
    if (a > c) {
        t = a; 
        a = c;
        c = t;
    }
    if (b > c) {
        t = b;
        b = c;
        c = t;
    }
    printf("排序后a、b、c的值为%d、%d、%d", a, b, c);
}

3. Running result:

请输入a、b、c的值，中间用空格隔开：4 1 7
排序后a、b、c的值为1、4、7

Recommended tutorial: "C Language Tutorial》

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