Java implementation to calculate the number of days in a certain month of a certain year

When calculating the number of days in a certain month of a certain year, you need to pay attention to leap years in ordinary years.

Analysis: The specific determination method of leap year depends on its determination conditions: there is a leap every four years, there is no leap for a hundred years, and there will be another leap every 400 years. To calculate the number of days in this month of the year, it is divided into big month and small month, and the special month is divided into February.

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Specific code:

import java.util.Scanner;
import java.text.MessageFormat;
public class Test02 {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.print("请输入一个4位数的年份（1900~2099）：");
        int year = input.nextInt();

        if(year >=1900 && year <= 2099){
            System.out.println("请输入月份（1~12）：");
            int month = input.nextInt();
            if(month >=1 && month <= 12){
             // 计算该年该月的天数
             // 大月和小月，特殊月份2月
                int day=31;
                switch(month){
                    case 4: case 6: case 9: case 11:
                        day=30;
                        break;
                    case 2:
                        // 判定条件：四年一闰 && 百年不闰 || 400年再闰
                        boolean isLeapYear=(year%4==0 && year%100!=0) || year%400==0;
                        //三元运算符判定
                        day= isLeapYear ? 29 : 28;
                        break;
                }
                String info = MessageFormat.format("{0}年{1}月{2}天",year,month,day);
                System.out.println(info);
            }else{
                System.out.println("请输入正确的月份");
            }
        }else{
            System.out.println("请输入一个1900~2099之间的年份");
        }
    }
}

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