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HomeJavaJavaBaseJava method to determine whether it is a date (code attached)

Java method to determine whether it is a date (code attached)

1、使用正则判断是否日期(推荐:java视频教程

public boolean isDate(String date) {
        /**
         * 判断日期格式和范围
         */
        String rexp = "^((\\d{2}(([02468][048])|([13579][26]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])))))|(\\d{2}(([02468][1235679])|([13579][01345789]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|(1[0-9])|(2[0-8]))))))";
 
        Pattern pat = Pattern.compile(rexp);
 
        Matcher mat = pat.matcher(date);
 
        boolean dateType = mat.matches();
 
        return dateType;
    }

2、使用SimpleDateFormat类设置日期格式,然后通过抛出异常来判断

public boolean isValidDate(String str) {
        boolean convertSuccess = true;
        // 指定日期格式为四位年/两位月份/两位日期,注意yyyy/MM/dd区分大小写;
        //如果想判断格式为yyyy-MM-dd,需要写成-分隔符的形式
        SimpleDateFormat format = new SimpleDateFormat("yyyy/MM/dd HH:mm");
        try {
             
            format.setLenient(false);
            format.parse(str);
        } catch (ParseException e) {
            // e.printStackTrace();
            // 如果抛出ParseException或者NullPointerException,就说明格式不对
            convertSuccess = false;
        }
        return convertSuccess;
    }

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