A gas card table:
id, userName, cardNo
1 aaa 222
BRefueling record table:
id, number, userName , cardNo,
1 1234 111
##2 234 bbb left join:select * from B b left join A a on a.userName = b.userName where b.userName=aaa
Due to the condition after on in the above SQL, userName corresponds to multiple entries in table A instead of one, and the result set is a Cartesian product. One item in table B satisfies the remaining two items in table A. The result is 2.
select * from B b left join A a on a.userName = b.userName and a.cardNo = b.cardNo where b.userName=aaa
Since in the above SQL, the two conditions after on can only find one unique piece of data in table A, so the result is how many pieces of data in table B satisfy where, and the result set will return how many pieces of data. Here is a piece of data returned
right join:
The following sql has the same effect as the above left join:
select * from A a right join B b on a.userName = b.userName and a.cardNo = b.cardNo where b.userName=aaainner join:
select * from A a inner join B b on a.userName = b.userName and a.cardNo = b.cardNo where a.userName=aaa
Let’s first look at the conditions after on. If a piece of data in table A corresponds to the two conditions of on and there is only one piece of data in B, then 2 pieces of data that satisfy the where condition are returned.
select * from B b inner join A a on a.userName = b.userName and a.cardNo = b.cardNo where a.userName=aaa
To summarize the above: Look at the condition behind on to see whether there is one or more pieces of data in the related table.
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