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This article brings you a detailed explanation of the usage of JavaScript's replace() when passing in the function. It has certain reference value. Friends in need can refer to it. I hope it will be helpful to you.
<script> var str = "a1ba2b"; var reg = /a.b/g; str = str.replace(reg,function(a,b){ console.log(a); console.log(b); return b == 0 ? a.replace("a","0") : a.replace("b","3"); }); console.log(str); /* 输出结果为: a1b 0//第一次匹配到a1b,将a置为0. a2b 3//第二次匹配到a2b,将b置为3. 01ba23//返回经过修改后的字符串 */ /* function(a,b,c)一共可以传入3个参数,第一个为匹配的字符串,第二个为匹配字符串的起始位置, 第三个为调用replace方法的字符串本身。可以缺省c或b、c。 */ </script>
Requirement: Change the number to the left of the floating point point every three digits Add a comma?
var str = '12000000.11'; var res = str.replace(/(\d)(?=(\d{3})+\.)/g, function(s1, s2) { console.log(arguments) // (\d{3})+ 虽然有+但只算一个捕获组 return s2 + ','; // 替换匹配成功的返回值 }); console.log(res) // 12,000,000.11 /* arguments的值为(匹配成功两次): ["2", "2", "000", 1, "12000000.11"] ["0", "0", "000", 4, "12000000.11"] 第一项:匹配成功返回的结果(预测断言匹配成功的值不会出现在匹配结果中) 第二项:第一个捕获组对应的值 第三项:第二个捕获组对应的值 第四项:匹配字符串的索引值 第五项:原始字符串 */
Analysis:
?=exp: Prediction assertion, the position where the assertion appears must match exp, otherwise the match fails, and the length will not be occupied after the match is successful.
/(\d)(?=(\d{3}) .)/g performs global matching. The string that successfully matched for the first time is: "2000000."
The second match The successful string is "0000."
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