How to implement substructure judgment of binary trees in PHP (code)

The content of this article is about how PHP implements the substructure judgment (code) of a binary tree. It has certain reference value. Friends in need can refer to it. I hope it will be helpful to you.

Input two binary trees A and B, and determine whether B is a substructure of A. (ps: We agree that the empty tree is not a substructure of any tree)
1. A subtree means that it contains a node, and it must contain all the nodes under this node, and the two trees end at the same time
2. The substructure can be any part of the A tree
Ideas:
1. The first recursion: two trees A and B, first find the same point in A as the root node of B. If the root of A No, then recurse the left and right subtrees of A to find
2. The second recursion: start the comparison from the root nodes of the two trees. During the traversal process, if the B tree is empty, return true; if B is not empty, A is empty, returns false
                                                                            -                                                                                                                                                                                                             ; Recurse the right subtree of A, the right subtree of B

HasSubtree(treeA,treeB)
    if(treeA->val==treeB->val)//根结点相同
        res=tree1HasTreeB(treeA.treeB)
    if !res
        res=HasSubtree(treeA->left.treeB)//第一层遍历
    if !res
        res=HasSubtree(treeA->right.treeB)//第一层遍历
    return res
tree1HasTreeB(treeA,treeB)
    //顺序不能变
    if treeB==null  //B到底的时候，就是true
        return true
    if treeA==null
        return false//B没到底，A到底了，就是false
    if treeA->val!=treeB->val //A和B的结点没对上
        return false
    //短路语法 ，如果前面的是false，直接返回false,后面不用走
    return tree1HasTreeB(treeA->left,treeB->left)&&tree1HasTreeB(treeA->right,treeB->right)

<?php
class TreeNode{
    public $val;
    public $left = NULL;
    public $right = NULL;
    public function __construct($val){
        $this->val = $val;
    }   
}


//构造两棵树
$node1=new TreeNode(1);
$node2=new TreeNode(2);
$node3=new TreeNode(3);
$node4=new TreeNode(4);
$node5=new TreeNode(5);


$treeA=$node1;
$node1->left=$node2;
$node1->right=$node3;
$node3->left=$node4;
$node3->right=$node5;

//var_dump($treeA);

$node6=new TreeNode(3);
$node7=new TreeNode(4);
$node6->left=$node7;
$treeB=$node6;
//var_dump($treeB);

function HasSubtree($pRoot1,$pRoot2){
        $res=false;
        if($pRoot1==null || $pRoot2==null) return $res;
        if($pRoot1->val==$pRoot2->val) $res=tree1HasTree2($pRoot1,$pRoot2);
        if(!$res) $res=HasSubtree($pRoot1->left,$pRoot2);
        if(!$res) $res=HasSubtree($pRoot1->right,$pRoot2);
        return $res;
}
function tree1HasTree2($treeA,$treeB){
        if($treeB==null) return true;
        if($treeA==null) return false;
        if($treeA->val!=$treeB->val) return false;
        return tree1HasTree2($treeA->left,$treeB->left)&&tree1HasTree2($treeA->right,$treeB->right);
}
var_dump(HasSubtree($treeA,$treeB));

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