本篇文章给大家带来的内容是关于C++中string&char *&char[]之间如何转换(示例),有一定的参考价值,有需要的朋友可以参考一下,希望对你有所帮助。
一、string转char*。
主要有三种方法可以将str转换为char*类型,分别是:data(); c_str(); copy();
1.data()方法,如:
string str = "hello"; const char* p = str.data();//加const 或者用char * p=(char*)str.data();的形式
同时有一点需要说明,这里在devc++中编译需要添加const,否则会报错invalid conversion from const char* to char *,这里可以再前面加上const或者在等号后面给强制转化成char*的类型。
下面解释下该问题,const char*是不能直接赋值到char*的,这样编译都不能通过,理由:假如可以的话,那么通过char*就可以修改const char指向的内容了,这是不允许的。所以char*要另外开辟新的空间,即上面的形式。
2.c_str()方法,如:
string str=“world”; const char *p = str.c_str();//同上,要加const或者等号右边用char*
3.copy()方法,如:
string str="hmmm"; char p[50]; str.copy(p, 5, 0);//这里5代表复制几个字符,0代表复制的位置, *(p+5)=‘\0’;//注意手动加结束符!!!
二、char * 转string。
可以直接赋值。
string s; char *p = "hello";//直接赋值 s = p;
这里有一点要说明,当声明了string类型变量s后,用printf("%s",s);是会出错的,因为“%s”要求后面的对象的首地址。但是string不是这样的一个类型。所以肯定出错。
三、string转char[]
这个由于我们知道string的长度,可以根据length()函数得到,又可以根据下标直接访问,所以用一个循环就可以赋值了。
string pp = "dagah"; char p[8]; int i; for( i=0;i<pp.length();i++) p[i] = pp[i]; p[i] = '\0'; printf("%s\n",p); cout<<p;
四、char[]转string
这里可以直接赋值。
char a[] = "abc"; std::string b = std::string(a);
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