


How to upload files in AngularJS? Detailed introduction to angularjs upload function
This article mainly talks about the function of uploading files in angularjs. Do you know how to upload files in angularjs? Angularjs is the front-end page. Do you know what is used in the background? Now let’s read this article
Use
AngularJS
Upload files
The frontend is
Angular
PageThe background uses
SpringBoot/SpirngMVC
Upload file
html
<p> <input id="fileUpload" type="file" /> <button ng-click="uploadFile()">上传</button></p>
js
$scope.upload = function(){ var form = new FormData(); var file = document.getElementById("fileUpload").files[0]; form.append('file', file); $http({ method: 'POST', url: '/upload', data: form, headers: {'Content-Type': undefined}, transformRequest: angular.identity }).success(function (data) { console.log('upload success'); }).error(function (data) { console.log('upload fail'); }) }
Note:
The default
'Content-Type'
of AngularJS isapplication/json
, by setting'Content -Type': undefined
, so the browser not only helps us setContent-Type
tomultipart/form-data
, but also fills in the currentboundary
,- ##If manually set to:
'Content-Type': multipart/form-data
, an exception will be thrown in the background:
the request was rejected because no multipart boundary was foundboundary
is a randomly generated string used to separate the beginning and end of text
- By setting
transformRequest: angular.identity
,
anjularjs transformRequest functionwill serialize our
formdata object, or you can not add
- Backend
@RequestMapping("/upload") public void uploadFile(@RequestParam(value = "file" , required = true) MultipartFile file) { //deal with file }
Note
- The file must pass @RequestParam annotation to get it, and you need to specify the value to get it
- This completes the uploading of the file
Pass other parameters while uploading the file
- html
<p> <input id="fileUpload" type="file" /> <button ng-click="ok()">上传</button><br> <input ng-model="user.username" /> <input ng-model="user.password" /> </p>
- js
$scope.ok = function () { var form = new FormData(); var file = document.getElementById("fileUpload").files[0]; var user =JSON.stringify($scope.user); form.append('file', file); form.append('user',user); $http({ method: 'POST', url: '/addUser', data: form, headers: {'Content-Type': undefined}, transformRequest: angular.identity }).success(function (data) { console.log('operation success'); }).error(function (data) { console.log('operation fail'); }) };
- Note
- You need to convert the Object to String before attaching it to the form, otherwise It will be directly converted into a string [Object, object]
- backend (if you want to see more, go to the PHP Chinese website
Learn from AngularJS Development Manual)
@RequestMapping("/upload") public Map<String, Object> upload(@RequestParam(value = "file") MultipartFile file, @RequestParam(value = "user", required = true) String user) { try (FileInputStream in = (FileInputStream) headImg.getInputStream(); FileOutputStream out = new FileOutputStream("filePathAndName")) { //将Json对象解析为UserModel对象 ObjectMapper objectMapper = new ObjectMapper(); UserModel userModel = objectMapper.readValue(user, UserModel.class); //保存文件到filePathAndName int hasRead = 0; byte[] bytes = new byte[1024]; while ((hasRead = in.read(bytes)) > 0) { out.write(bytes, 0, hasRead); } } catch (IOException e) { e.printStackTrace(); } }
Note
ObjectMapper
is
com .fasterxml.jackson.databind.ObjectMapper
UseThis article The article ends here (if you want to see more, go to the PHP Chinese websiteAngularJS
Upload files
AngularJS User Manual to learn). If you have any questions, you can leave a message below.
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