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Code to upload ajax files using FormData()

不言
不言Original
2018-08-02 13:44:371658browse

This article introduces to you the code about using FormData() to upload ajax files. It has certain reference value. Friends in need can refer to it. I hope it will be helpful to you.

HTML:

<form action="">
    
        <input type="file" id="file1" name="">
    
        <br>
    
        <input type="file" id="file2" name="">
    
        <br>
    
        <input type="button" value="保存">
    
    </form>

JS:

      $("input[type=&#39;button&#39;]").on(&#39;click&#39;, upfile);

        /**
         * [upfile 文件上传]
         * @return {[Object]} [成功回调]
         */
        function upfile() {
            
            var formData = new FormData();

            formData.append("接收字段1", document.getElementById(&#39;file1&#39;).files[0]);
            // console.log(document.getElementById(&#39;file1&#39;).files[0]);
            
            formData.append("接收字段2", document.getElementById(&#39;file2&#39;).files[0]);
            // console.log(document.getElementById(&#39;file2&#39;).files[0]);

            $.ajax({

                url: &#39;接口地址url&#39;,

                type: &#39;POST&#39;,

                data: formData, // 上传formdata封装的数据包

                dataType: &#39;JSON&#39;,

                cache: false, // 不缓存

                processData: false, // jQuery不要去处理发送的数据

                contentType: false, // jQuery不要去设置Content-Type请求头

                success: function(data) { // 成功回调

                    console.log(data);

                }

            });
        
        }

Successful effect:


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