Explanation on php json_encode not supporting object private attributes

This article introduces the solution for php json_encode that does not support the private properties of objects. json_encode can convert the object into json format, and use json_decode to restore it to the object.

But if the object contains private attributes, the private attributes will be lost after json_encode is executed.

Example: json_encode loses object private attributes

<?php// 用户类class user{

    public $id = 1;    public $name = &#39;fdipzone&#39;;    public $profession = &#39;programmer&#39;;    private $age = 18;

}// 对象$oUser = new User;// json_encode$json = json_encode($oUser);echo $json;// json_decode$oUser = json_decode($json);
var_dump($oUser);?>

Output:

{"id":1,"name":"fdipzone","profession":"programmer"}object(stdClass)[2]  public 'id' => int 1
  public 'name' => string 'fdipzone' (length=8)  public 'profession' => string 'programmer' (length=10)

After executing json_encode, the private attribute age is lost.

Solution to the loss of private attributes of the object after json_encode

The modified code is as follows:

<?php// 用户类class user implements JsonSerializable{

    public $id = 1;    public $name = &#39;fdipzone&#39;;    public $profession = &#39;programmer&#39;;    private $age = 18;    // 实现的抽象类方法，指定需要被序列化JSON的数据
    public function jsonSerialize() {
        $data = [];        foreach ($this as $key=>$val){            if ($val !== null) $data[$key] = $val;
        }        return $data;
    }

}// 对象$oUser = new User;// json_encode$json = json_encode($oUser);echo $json;// json_decode$oUser = json_decode($json);
var_dump($oUser);?>

Output:

{"id":1,"name":"fdipzone","profession":"programmer","age":18}object(stdClass)[2]  public 'id' => int 1
  public 'name' => string 'fdipzone' (length=8)  public 'profession' => string 'programmer' (length=10)  public 'age' => int 18

After specifying the data that needs to be serialized into JSON, json_encode can read the private attribute age.

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