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Detailed explanation and implementation code for judging the number of palindromes in javascript (picture and text tutorial)

亚连Original: 2018-05-19 11:43:063786browse

This article mainly introduces the detailed explanation and implementation code of javascript to determine the number of palindromes. Friends in need can refer to it

javascript to determine the number of palindromes

Summary:

"Palindrome" refers to a sentence that can be read both forward and backward. It is a rhetorical method and word game that has existed in ancient and modern times, both at home and abroad, such as "I am a human being" "People, everyone for me" etc. In mathematics, there is also a type of number with such characteristics, which is called a palindrome number.

Suppose n is an arbitrary natural number. If the digits of n are If the natural number n1 obtained by reverse arrangement is equal to n, then n is called a palindrome number. For example, if n=1234321, then n is called a palindrome number; but if n=1234567, then n is not a palindrome number.

Note:

1. Even numbers also have palindromes 124421
2. Decimals do not have palindromes

Implementation code:

<html> 
  <head> 
    <meta http-equiv="Content-Type" content="text/html;charset=gb2312"/> 
    <title>test</title> 
    <script type="text/javascript"> 
      var number = parseInt(window.prompt("输入回文数")); 
      if(daozhi(number) == number) { 
        document.writeln(number + "是回文数"); 
      } else { 
        document.writeln(number + "不是回文数");  
      } 
       
      /*整数的倒置*/ 
      function daozhi(num) { 
        var newNumber = 0; 
         
        while(num != 0) { 
          newNumber *= 10; 
          newNumber =newNumber + (num % 10); 
          num = Math.floor(num/10); 
        } 
         
        return newNumber; 
      } 
       
    </script> 
  </head> 
  <body> 
  </body> 
</html>

The above is what I compiled for everyone. I hope it will be helpful to everyone in the future.

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