PHP classic algorithm bridge crossing

The content of this article introduces the classic algorithm of PHP. I will share it with you here. Friends in need can refer to it

<?php /*
假设某人有100，000现金。
每次经过一次路口需要进行一次缴费。
身上钱大于5000，则缴费5%
身上钱小于5000，则缴费5000.
问：此人可以经过多少次这个路口？
*/for($i=100000,$count=0;$i>=5000;){    $count +=1;    if($i>50000){        $i =$i-$i*0.05;
    }else{        $i -=5000;
    }    echo &#39;第&#39;.$count.&#39;次过桥，剩下[&#39;.$i.&#39;]&#39;."</br>";
}?>

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