Home >Web Front-end >JS Tutorial >Ajax upload and preview images (with code)

Ajax upload and preview images (with code)

php中世界最好的语言Original: 2018-04-03 15:11:392271browse

This time I will bring you Ajax upload and preview pictures (with code). What are the precautions for Ajax upload and preview pictures? The following is a practical case, let's take a look.

1. Directly use the simplest ajax to asynchronously upload images and preview

html:

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>图片上传 | cookie</title>
</head>
<body>
  file: <input type="file" id="images" name="image" /><br><br>
  desc: <input type="text" id="desc" name="desc" /><br><br>
  <input type="button" value="upload" onclick="upload();">
  
  <p class="images"></p>
  
<script type="text/javascript" src="js/jquery-1.12.4.min.js"></script>
<script type="text/javascript" src="js/upload.js"></script>
<script type="text/javascript">
  function upload() {
    $.ajaxFileUpload({
      url : 'upload.htm',
      fileElementId : 'images',
      dataType : 'json',
      data : {desc : $("#desc").val()},
      success : function(data) {
        var html = $(".images").html();
        html += '<img width="100" height="100" src="/HotelManager/upload/&#39; + data.url + &#39;">'
        $(".images").html(html);
      }
    })
    return false;
  }
</script>
</body>
</html>

servlet ：

protected void doPost(HttpServletRequest request, HttpServletResponse response)
      throws ServletException, IOException {
    DiskFileItemFactory factory = new DiskFileItemFactory();
    
    ServletFileUpload upload = new ServletFileUpload(factory);
    
    String path = request.getServletContext().getRealPath("/upload");
    String name = null;
    try {
      List<FileItem> items = upload.parseRequest(request);
      for (FileItem item : items) {
        if(item.isFormField()){
          System.out.println(item.getFieldName() + ": " + item.getString());
        } else {
          name = item.getName();
          item.write(new File(path,name));
        }
      }
      PrintWriter out = response.getWriter();
      out.print("{");
      out.print("url:\"" + name +"\"");
      out.print("}");
      
    } catch (Exception e) {
      e.printStackTrace();
    }
  }

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

Ajax upload and preview images (with code)

Related articles