


Implementing refresh-free user login based on Ajax technology (with code)
This time I will bring you how to implement non-refresh user login based on Ajax technology User login (with code), what are the precautions to implement non-refresh user login based on Ajax technology, The following is a practical case, let’s take a look.
The code is as follows:
// JScript 文件 function usersLogon() { var userName = document.getElementById("txtuserName").value; var password = document.getElementById("txtpassword").value; var checkCode = document.getElementById("txtCheckCode").value; var response = userControl_logon.CheckCodeIsRight(checkCode).value; if(userName == "") { document.getElementById("txtuserName").focus(); return false; } else if(password == "") { document.getElementById("txtpassword").focus(); return false; } else if(checkCode =="") { document.getElementById("txtCheckCode").focus(); return false; } else { if(response == true) { //判断用户是否存在 userControl_logon.userNameAndPasswordIsExist(userName,password,userNameIsRight); } else { alert("验证码出错"); userControl_logon.checkCodeOperaotr(refreshCheckCode); document.getElementById("txtpassword").value = ""; } } } function userNameIsRight(res) { var userName = document.getElementById("txtuserName").value; if(res.value == true) { //用户存在,但要看此用户有没有进入管理留言版权限, userControl_logon.userNameIsRight(userName,CallBack); } else { alert("用户名或密码错误"); document.getElementById("txtpassword").value = ""; OnLoad_checkCode(); } } function CallBack(res) { if(res.value == true) { hideLogon(); var url = userControl_logon.returnUrl(); if ( url.value == 404) { showDefault(); } else { document.getElementById("Url").innerHTML = '<a>' + url.value + '</a>' } } else { alert("对不起你的权限不够"); document.getElementById("txtpassword").value = ""; OnLoad_checkCode(); } } //隐藏登录框 function hideLogon() { var element = document.getElementById("hideLogon") element.style.display = "none" } //显示返回首页 function showDefault() { var element = document.getElementById("Returndefault") element.style.display = "block" } function OnLoad_checkCode() { userControl_logon.checkCodeOperaotr(refreshCheckCode); document.getElementById("txtuserName").focus(); // return false; } ///重新得到新的验证吗 function refreshCheckCode(res) { document.getElementById("txtCheckCode").value = ""; document.getElementById("lblNumber").innerHTML = res.value; } function abce() { alert(document.getElementById("lblNumber").value) }
The following code
using System; using System.Data; using System.Configuration; using System.Collections; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.Drawing; using LHB_SQL_2005; public partial class userControl_logon : System.Web.UI.UserControl { protected void Page_Load(object sender, EventArgs e) { if (!this.IsPostBack) { AjaxPro.Utility.RegisterTypeForAjax(typeof(userControl_logon)); } } [AjaxPro.AjaxMethod] public static string checkCodeOperaotr() { string _checkCode = GeneralMethod.GenerateCheckCode(); System.Web.HttpContext.Current.Session["checkCode"] = _checkCode; //返回验证码 return _checkCode; } /// <summary> /// 判断验证是否正确 /// </summary> /// <param> /// <returns></returns> [AjaxPro.AjaxMethod] public static bool CheckCodeIsRight(string checkCode) { string _checkCode = (string)(System.Web.HttpContext.Current.Session["checkCode"]); if (_checkCode == checkCode) { return true; } else { return false; } } /// <summary> /// 判断用户名及密码添加是否正确 /// </summary> /// <param>用户名 /// <param>用户名密码 /// <returns>bool</returns> [AjaxPro.AjaxMethod] public static bool userNameAndPasswordIsExist(string userName, string _password) { string password = GeneralMethod.ToEncryptPassword(_password); string executeString = "SELECT COUNT(*) FROM users WHERE userName = '" + userName.ToString() + "' AND password = '" + password + "'"; int count = int.Parse(GetCommand.ExecuteScalar(executeString)); if (count == 1) { System.Web.HttpContext.Current.Session["userName"] = userName; return true; } else { return false; } } /// <summary> /// 判断用户是不是有这进入管理留言版的权限 /// </summary> /// <param>用户名 /// <returns></returns> [AjaxPro.AjaxMethod] public static bool userNameIsRight(string userName) { string executeString = "SELECT [right] FROM role WHERE usersId = (select userNameId from users where userName = '" + userName + "')"; int count = int.Parse(GetCommand.ExecuteScalar(executeString)); if (count > 0) { return true; } else { return false; } } /// <summary> /// 返回Url值 /// </summary> /// <returns></returns> [AjaxPro.AjaxMethod] public static string returnUrl() { string url = ""; try { url = System.Web.HttpContext.Current.Session["url"].ToString(); } catch { url ="404"; } return url; } }
The following is the page code
<script> </script> <script> </script> <link> <link> <p> </p>
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I believe you have mastered the method after reading the case in this article, and there will be more exciting things Please pay attention to other related articles on php Chinese website!
Recommended reading:
AJAX implementation without refreshing login
Summary of Ajax that novices must learn
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