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This time I will bring you a detailed explanation of the steps for js to request servlet to implement ajax request. What are the precautions for js to request servlet to implement ajax request? The following is a practical case, let's take a look.
ajax request is a refresh-free user experience that can send two asynchronous requests, GET and POST. The current record is as follows:GET request:
function sendRequestByGet(){ //定义异步请求对象 var xmlReq; //检测浏览器是否直接支持ajax if(window.XMLHttpRequest){//直接支持ajax xmlReq=new XMLHttpRequest(); }else{//不直接支持ajax xmlReq=new ActiveObject('Microsoft.XMLHTTP'); } //设置回调函数 xmlReq.onreadystatechange=function(){ if (xmlReq.readyState==4&&xmlReq.status==200) { //获取服务器的响应值 var result=xmlReq.responseText; //后续操作 alert(result); } }; //创建异步get请求 var url="Hello?name=zhangsan"; xmlReq.open("GET",url,true); //发送请求 xmlReq.send(null); }
POST request :
function sendRequestByPost(){ //定义异步请求对象 var xmlReq; //检测浏览器是否直接支持ajax if(window.XMLHttpRequest){//直接支持ajax xmlReq=new XMLHttpRequest(); }else{//不直接支持ajax xmlReq=new ActiveObject('Microsoft.XMLHTTP'); } //设置回调函数 xmlReq.onreadystatechange=function(){ if (xmlReq.readyState==4&&xmlReq.status==200) { //获取服务器的响应值 var result=xmlReq.responseText; //后续操作 alert(result); } }; //创建异步Post请求 var url="Hello"; xmlReq.open("POST",url,true); xmlReq.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); //发送请求 var data="name=lisi"; xmlReq.send(data); }
ajax request servlet:
@Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { String name=req.getParameter("name"); PrintWriter out = resp.getWriter(); out.print(name); }Effect: I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related matters on the php Chinese website article! Recommended reading:
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