How to use AjaxFileUpload to upload multiple files
这次给大家带来怎么用AjaxFileUpload实现多文件上传,用AjaxFileUpload实现多文件上传的注意事项有哪些,下面就是实战案例,一起来看一下。
本文重点给大家介绍AjaxFileUpload+Struts2实现多文件上传功能,具体实现代码大家参考下本文。
单文件和多文件的实现区别主要修改两点,
一是插件ajaxfileupload.js里接收file文件ID的方式
二是后台action是数组形式接收
1、ajaxFileUpload文件下载地址http://www.phpletter.com/Demo/AjaxFileUpload-Demo/
2、引入jquery-1.8.0.min.js、ajaxFileUpload.js文件
3、文件上传页面核心代码
<script> function fileUpload() { var files = ['file1','file2','file3']; //将上传三个文件 ID 分别为file2,file2,file3 $.ajaxFileUpload( { url : 'fileUploadAction', //用于文件上传的服务器端请求地址 secureuri : false, //一般设置为false fileElementId : files, //文件上传的id属性 <input type="file" id="file" name="file" /> dataType : 'json', //返回值类型 一般设置为json success : function(data, status) { var fileNames = data.fileFileName; //返回的文件名 var filePaths = data.filePath; //返回的文件地址 for(var i=0;i<data.fileFileName.length;i++){ //将上传后的文件 添加到页面中 以进行下载 $("#down").after("<tr><td height='25'>"+fileNames[i]+ "<td><a href='downloadFile?downloadFilePath="+filePaths[i]+"'>下载") } } }) } </script>
以上fileElementId属性接收的files参数为['file1','file2','file3']
由于是多文件,所以我们需要修改ajaxfileupload.js 找到以下代码
var oldElement = jQuery('#' + fileElementId); var newElement = jQuery(oldElement).clone(); jQuery(oldElement).attr('id', fileId); jQuery(oldElement).before(newElement); jQuery(oldElement).appendTo(form);
修改为:
for(var i in fileElementId){ var oldElement = jQuery('#' + fileElementId[i]); var newElement = jQuery(oldElement).clone(); jQuery(oldElement).attr('id', fileId); jQuery(oldElement).before(newElement); jQuery(oldElement).appendTo(form); }
4、文件上传Action
public class FileAction { private File[] file; //文件 private String[] fileFileName; //文件名 private String[] filePath; //文件路径 private String downloadFilePath; //文件下载路径 private InputStream inputStream; /** * 文件上传 * @return */ public String fileUpload() { String path = ServletActionContext.getServletContext().getRealPath("/upload"); File file = new File(path); // 判断文件夹是否存在,如果不存在则创建文件夹 if (!file.exists()) { file.mkdir(); } try { if (this.file != null) { File f[] = this.getFile(); filePath = new String[f.length]; for (int i = 0; i <p style="text-align: left;">5、struts配置</p><pre class="brush:php;toolbar:false">nbsp;struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN" "http://struts.apache.org/dtds/struts-2.0.dtd"> <struts> <package> <!-- 文件上传 --> <action> <result> <param>text/html </result> </action> </package> <package> <!-- 文件下载 --> <action> <result> <param>application/octet-stream <param>inputStream <param>attachment;filename=${fileName} <param>4096 </result> </action> </package> </struts>
浏览器中输入:http://localhost:8080/struts_ajaxfileupload/index.jsp 即可进行文件上传
如图:
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