JQuery Select All Inverse Selection Second Failure Solution

This article mainly brings you an article to solve the problem of JQuery full selection/inverse selection failing for the second time. The editor thinks it’s pretty good, so I’ll share it with you now and give it as a reference. Let’s follow the editor to take a look, I hope it can help everyone.

Recently, I encountered a problem in the project. When testing the select/unselect function, when the parent box is selected/unselected for the first time, the all-selected/unselected state of the sub-box can be synchronized. , and then click the parent box, the child box will not respond.

The key to the general structure of the original code is as follows:

function selectAll(obj){
    $('input[name="xxx[]"]').attr("checked",obj.checked);
}

<input type="checkbox" id="mother" name="mother" onclick="selectAll(this);"/>全选

<input type="checkbox" id="son1" name="xxx[]" />子框<input type="checkbox" id="son2" name="xxx[]" />子框<input type="checkbox" id="son3" name="xxx[]" />子框<input type="checkbox" id="son4" name="xxx[]" />子框

Step 1: Try a positive wave:

function selectAll(obj){
   if(obj.checked) {
    $('input[name="xxx[]"]').attr("checked", true);
   } else {
    $('input[name="xxx[]"]').removeAttr("checked");
   }
}

Death ----- has no effect at all, discard it.

Step 2: After a quick search on the Internet, I found that this problem is relatively common. Among people who have encountered this problem, I should be thousands of miles away. I clicked on a few and looked at them. They basically said that using prop instead of attr can solve the problem. The solution is as follows:

However, the version used in the project is lower than 1.6 and I was told that the latest It is best not to change the version and discard it.

Step 3: There is no choice but to abandon JQuery... Try to use native js writing method. The code is as follows:

function selectAll(obj){
 var xxx = document.getElementsByName("xxx[]");
  if(obj.checked) {
   for(var i = 0;i < xxx.length;i++) {
    xxx[i].checked = true;
   }
  } else {
   for(var i = 0;i < xxx.length;i++) {
    xxx[i].checked = false;
   }
  }
}

Test it and solve it smoothly. In fact, it is a small problem, but it gave me some inspiration. I cannot be limited to one box. If I think about the problem from another angle, I can often solve the problem better.

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