Simple usage instructions for the opendir function in php?

opendir() FunctionOpen a directory handle. If successful, the directory handle resource is returned. Returns FALSE on failure. If the path is not a legal directory, or the directory cannot be opened due to licensing restrictions or filesystem errors, an E_WARNING level error is thrown. You can hide the error output of opendir() by adding '@' before the function name

opendir() function syntax

opendir(path,context);

Parameters	Description
path	Required. Specifies the directory path to be opened.
context	Optional. Specifies the environment for directory handles. context is a set of options that modify the behavior of a directory stream.

opendir() function example, the code is as follows:

$dirs ='./';//指定当前上当 
if( is_dir( $dirs ) ) 
{ 
 $hanld = opendir($dirs); 
 
 while (($file = readdir($hanld)) !== false) 
 { 
   echo "文件名: " . $file . "<br />"; 
 } 
 closedir($hanld); 
} 
else 
{ 
 echo &#39;不是目录&#39;; 
}

Output result:
File name: a
File name: b
File name:www.php.cn

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