Usage of php directory traversal opendir() function

opendir() FunctionOpen a directory handle. This function returns the directory handle resource if successful. Returns FALSE on failure. If the path is not a legal directory, or the directory cannot be opened due to licensing restrictions or file system errors, an E_WARNING level error is thrown. You can hide the error output of opendir() by adding '@' before the function name.

opendir() function example, code is as follows:

<?php  
$dir = "./"; 
 
// open a known directory, and proceed to read its contents  
if (is_dir($dir))  
{  
if ($dh = opendir($dir)) {  
while (($file = readdir($dh)) !== false) {  
echo "filename: $file : filetype: " . filetype($dir . $file) . "n"."<br />";  
}
closedir($dh);  
}  
}  
?>

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