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<?php header('content-type:text/html;charset=utf-8'); /* 普通方法,存放类内,只有一份 静态方法,也是存放于类内,只有一份 区别在于:普通方法需要对象去调用,需要绑定$this 即,普通方法,必须要有对象,然后让对象来调用 而静态方法,不属于哪一个对象,因此不需要绑定$this 即,不需要对象也可以调用 */ class Human{ static public $head=1; public function easyeat(){ echo '普通方法吃饭<br />'; } static public function eat(){ echo '静态方法吃饭<br />'; } public function intro(){ echo $this->name; } } Error_reporting(E_ALL|E_STRICT); //此时没有对象!方法可以执行 Human::eat(); /* 以下方法easyeat是一个非静态方法,就由对象来调用,但,用类来调用此方法来也可以执行,而严格状态下,此方法会执行,同时报错, Strict Standards: Non-static method Human::easyeat() should not be called statically in D:\application\PHPnow-1.5.6\htdocs\yan18\types\staticfun.php on line 32 */ Human::easyeat(); /* 接上,从逻辑来理解,如果用类名静态调用非静态(普通)方法 比如:intro() 那么,这个$this是指哪个对象呢?? 因此会报错,因为找不到对象! Fatal error: Using $this when not in object context in D:\application\PHPnow-1.5.6\htdocs\yan18\types\staticfun.php on line 23 */ Human::intro(); /* 如上分析,其实,非静态方法,是不能由类名静态调用的,但目前,php中的面向对象检测不够严格,只要静态方法中没有$this关键字,就会转化成静态方法来处理! */ $li=new Human(); $li->eat(); /* 总结: 类》访问->静态方法(类的方法)->可以 类》访问->普通方法(对象的方法)->不可以(虽然方法里不用$this关键字时,可以!但不支持这种写法) 对象》访问》静态方法(类的方法)->可以 对象》访问》普通方法(对象的方法)->可以 */ ?>
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