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Share an example of writing login and registration using python's Tkinter

零下一度
零下一度Original
2017-07-02 10:51:082569browse

This article mainly introduces in detail the login and registration interface written by Tkinter based on python, which has certain reference value. Interested friends can refer to

tkinter creation The login registration interface is for your reference. The specific content is as follows


import tkinter as tk
from tkinter import messagebox
 
#设置窗口居中
def window_info():
 ws = window.winfo_screenwidth()
 hs = window.winfo_screenheight()
 x = (ws / 2) - 200
 y = (hs / 2) - 200
 print("%d,%d" % (ws, hs))
 return x,y
 
#设置登陆窗口属性
window = tk.Tk()
window.title('欢迎使用停车场收费系统')
a,b=window_info()
window.geometry("450x300+%d+%d"%(a,b))
 
#登陆界面的信息
tk.Label(window,text="停车场收费系统",font=("宋体",32)).place(x=80,y=50)
tk.Label(window,text="账号:").place(x=120,y=150)
tk.Label(window,text="密码:").place(x=120,y=190)
#显示输入框
var_usr_name = tk.StringVar()
#显示默认账号
var_usr_name.set('1400370101')
entry_usr_name=tk.Entry(window,textvariable=var_usr_name)
entry_usr_name.place(x=190,y=150)
var_usr_pwd = tk.StringVar()
#设置输入密码后显示*号
entry_usr_pwd = tk.Entry(window,textvariable=var_usr_pwd,show='*')
entry_usr_pwd.place(x=190,y=190)
 
#登陆函数
def usr_login():
 #获取输入的账号密码
 usr_name = var_usr_name.get()
 usr_pwd = var_usr_pwd.get()
 #获取存储的账户信息,此处使用的是数据库,调用数据库查询函数,也可以使用其他方式,如文件等
 dicts = SQL.load('login')
 print(dicts)
 bool = False
 for row in dicts:
 print(row.get("name"))
 if usr_name == row["name"]:
  bool = True
  pwd = row["password"]
  print(row)
 if bool == True:
 if usr_pwd == pwd:
  tk.messagebox.showinfo(title='Welcome', message='How are you?' +usr_name)
  mainwindow()
 else:
  tk.messagebox.showerror(message='对不起,输入错误,请重试!')
 else:
 is_sign_up = tk.messagebox.askyesno('Welcome', '您还没有注册,是否现在注册呢?')
 if is_sign_up:
  usr_sign_up()
#注册账号
def usr_sign_up():
 def sign_to_Pyhon():
 np = new_pwd.get()
 npc = new_pwd_confirm.get()
 nn = new_name.get()
 
 dicts = SQL.load('login')
 print(dicts)
 bool = False
 for row in dicts:
  if nn == row["name"]:
  bool = True
  print(row)
 if np!=npc:
  tk.messagebox.showerror('对不起','两次密码输入不一致!')
 elif bool:
  tk.messagebox.showerror(('对不起','此账号已经存在!'))
 else:
  try:
  SQL.insert_login(str(nn),str(np))
  tk.messagebox.showinfo('Welcome','您已经注册成功!')
  except:
  tk.messagebox.showerror(('注册失败!'))
  window_sign_up.destroy()
 #创建top窗口作为注册窗口
 window_sign_up = tk.Toplevel(window)
 window_sign_up.geometry('350x200')
 window_sign_up.title('注册')
 
 new_name = tk.StringVar()
 new_name.set('1400370115')
 tk.Label(window_sign_up,text='账号:').place(x=80,y=10)
 entry_new_name = tk.Entry(window_sign_up,textvariable=new_name)
 entry_new_name.place(x=150,y=10)
 
 new_pwd = tk.StringVar()
 tk.Label(window_sign_up, text='密码:').place(x=80, y=50)
 entry_usr_pwd = tk.Entry(window_sign_up,textvariable=new_pwd,show='*')
 entry_usr_pwd.place(x=150, y=50)
 
 new_pwd_confirm = tk.StringVar()
 tk.Label(window_sign_up,text='再次输入:').place(x=80,y=90)
 entry_usr_pwd_again = tk.Entry(window_sign_up,textvariable=new_pwd_confirm,show='*')
 entry_usr_pwd_again.place(x=150, y=90)
 
 btn_again_sign_up = tk.Button(window_sign_up,text='注册',command=sign_to_Pyhon)
 btn_again_sign_up.place(x=160,y=130)
 
#登陆和注册按钮
btn_login = tk.Button(window,text="登陆",command=usr_login)
btn_login.place(x=170,y=230)
btn_sign_up = tk.Button(window,text="注册",command=usr_sign_up)
btn_sign_up.place(x=270,y=230)
 
window.mainloop()

This is the login registration interface I wrote. Using tkinter, you can achieve simple login and account registration. , mainly using Label, Entry and Button components.

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