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HomeBackend DevelopmentPython TutorialShare an example tutorial of tkinter login and registration interface

import tkinter as tk
from tkinter import messagebox

#设置窗口居中
def window_info():
    ws = window.winfo_screenwidth()
    hs = window.winfo_screenheight()
    x = (ws / 2) - 200
    y = (hs / 2) - 200
    print("%d,%d" % (ws, hs))
    return x,y

#设置登陆窗口属性
window = tk.Tk()
window.title('欢迎使用停车场收费系统')
a,b=window_info()
window.geometry("450x300+%d+%d"%(a,b))

#登陆界面的信息
tk.Label(window,text="停车场收费系统",font=("宋体",32)).place(x=80,y=50)
tk.Label(window,text="账号:").place(x=120,y=150)
tk.Label(window,text="密码:").place(x=120,y=190)
#显示输入框
var_usr_name = tk.StringVar()
#显示默认账号
var_usr_name.set('1400370101')
entry_usr_name=tk.Entry(window,textvariable=var_usr_name)
entry_usr_name.place(x=190,y=150)
var_usr_pwd = tk.StringVar()
#设置输入密码后显示*号
entry_usr_pwd = tk.Entry(window,textvariable=var_usr_pwd,show='*')
entry_usr_pwd.place(x=190,y=190)

#登陆函数
def usr_login():
    #获取输入的账号密码
    usr_name = var_usr_name.get()
    usr_pwd = var_usr_pwd.get()
    #获取存储的账户信息,此处使用的是数据库,调用数据库查询函数,也可以使用其他方式,如文件等
    dicts = SQL.load('login')
    print(dicts)
    bool = False
    for row in dicts:
        print(row.get("name"))
        if usr_name == row["name"]:
            bool = True
            pwd = row["password"]
            print(row)
    if bool == True:
        if usr_pwd == pwd:
            tk.messagebox.showinfo(title='Welcome', message='How are you?' +usr_name)
            mainwindow()
        else:
            tk.messagebox.showerror(message='对不起,输入错误,请重试!')
    else:
        is_sign_up = tk.messagebox.askyesno('Welcome', '您还没有注册,是否现在注册呢?')
        if is_sign_up:
            usr_sign_up()
#注册账号
def usr_sign_up():
    def sign_to_Pyhon():
        np = new_pwd.get()
        npc = new_pwd_confirm.get()
        nn = new_name.get()

        dicts = SQL.load('login')
        print(dicts)
        bool = False
        for row in dicts:
            if nn == row["name"]:
                bool = True
                print(row)
        if np!=npc:
            tk.messagebox.showerror('对不起','两次密码输入不一致!')
        elif bool:
            tk.messagebox.showerror(('对不起','此账号已经存在!'))
        else:
            try:
                SQL.insert_login(str(nn),str(np))
                tk.messagebox.showinfo('Welcome','您已经注册成功!')
            except:
                tk.messagebox.showerror(('注册失败!'))
            window_sign_up.destroy()
   #创建top窗口作为注册窗口
    window_sign_up = tk.Toplevel(window)
    window_sign_up.geometry('350x200')
    window_sign_up.title('注册')

    new_name = tk.StringVar()
    new_name.set('1400370115')
    tk.Label(window_sign_up,text='账号:').place(x=80,y=10)
    entry_new_name = tk.Entry(window_sign_up,textvariable=new_name)
    entry_new_name.place(x=150,y=10)

    new_pwd = tk.StringVar()
    tk.Label(window_sign_up, text='密码:').place(x=80, y=50)
    entry_usr_pwd =   tk.Entry(window_sign_up,textvariable=new_pwd,show='*')
    entry_usr_pwd.place(x=150, y=50)

    new_pwd_confirm = tk.StringVar()
    tk.Label(window_sign_up,text='再次输入:').place(x=80,y=90)
    entry_usr_pwd_again = tk.Entry(window_sign_up,textvariable=new_pwd_confirm,show='*')
    entry_usr_pwd_again.place(x=150, y=90)

    btn_again_sign_up = tk.Button(window_sign_up,text='注册',command=sign_to_Pyhon)
    btn_again_sign_up.place(x=160,y=130)

#登陆和注册按钮
btn_login = tk.Button(window,text="登陆",command=usr_login)
btn_login.place(x=170,y=230)
btn_sign_up = tk.Button(window,text="注册",command=usr_sign_up)
btn_sign_up.place(x=270,y=230)

window.mainloop()

This is the login registration interface I wrote. Using tkinter, you can implement simple login and account registration. The main components used are Label, Entry and Button components.

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