Examples summarizing the usage skills of PHP bit operators
Explain through an example:
<?php //1.位运算符两边的值必须是整形和浮点型,当是其它类型的值时会先转换成整形和浮点型再来参与位运算; //而逻辑运算符两边参与运算的值必须是布尔型; var_dump(12&13);//输出 int 12 //12转换成32位的二进制数为:00000000 00000000 00000000 00001100 //13转换成32位的二进制数为:00000000 00000000 00000000 00001101 //按位运算后得到的值为 00000000 00000000 00000000 00001100 ,等于12 var_dump('A'&'a');//输出string 'A';因为A=65,a=97 var_dump('A'&97);//输出int 0;因为字符串A会先转换为整数的0后再参与位运算 //2.位运算与逻辑运算不同没有短路特性 $a=3; $b=10; if($a>5&&$b++<100) { echo "1111111111"; } echo $b."<br>";//输出$b=10,逻辑运算短路,$b没有自加; if($a>5&$b++<100) { echo "1111111"; } echo $b."<br>";//输出$b=11,位运算不短路,$b自加; //3.按位非,按位异或等比较简单,这里不做过多讲叙;现在讲讲按位左移和按位右移动 var_dump(12>>2);//输出int 3 var_dump(12<<2);//输出int 48 //可以发现,左移几位就相当于乘以2的多少次方;按位右移就相当于除以2的多少次方; ?>
(1) Determine whether the int type variable a is an odd number or an even number
a&1 = 0 even number
a&1 = 1 odd number
(2) Take the k-th bit of int type variable a (k=0,1,2...sizeof(int)), that is, a>>k&1
(3) Change the int type variable Clear the k-th bit of a to 0, that is, a=a&~(1
(4) Set the k-th bit of int type variable a to 1, that is, a=a |(1
(5) The int type variable is circularly shifted to the left k times, that is, a=a16-k (assume sizeof(int)=16 )
(6) The int type variable a is shifted to the right k times in a loop, that is, a=a>>k|a
(7) Average of integers
For two integers x, y, if you use (x+y)/2 to find the average, overflow will occur because x+y may be greater than INT_MAX, but we Knowing that their average value will definitely not overflow, we use the following algorithm:
int average(int x, int y) //返回X,Y 的平均值 { return (x&y)+((x^y)>>1); }
(8) Determine whether an integer is a power of 2. For a number x >= 0, determine whether it is 2 The power of Without overflow)
a % (2^n) is equivalent to a & (2^n – 1)
(12) The multiplication operation is converted into a bit operation (without In the case of overflow)
a * (2^n) is equivalent to a
(13) The division operation is converted into a bit operation (in the case of no overflow )
a / (2^n) is equivalent to a>> n
Example: 12/8 == 12>>3
(14) a % 2 is equivalent to a & 1
(15) if (x == a) x= b;
else x= a;
Equivalent to x= a ^ b ^ x;
(16) The opposite number of In the case of 32 bits, shift left
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