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Stability and significance of sorting algorithm
Bubble sort
Complexity and stability Sex
Selection sort
Insertion sort
Hill sort
Quick sort
Comparison of efficiency of common sorting algorithms
In the sequence to be sorted, there are records with the same keywords. After sorting, the relative order of these records remains unchanged, then the sorting algorithm is stable.
Unstable sorting cannot complete sorting of multiple keywords. For example, integer sorting, the higher the number of digits, the higher the priority, sorting from high digits to low digits. Then the sorting of each bit requires a stable algorithm, otherwise the correct result cannot be obtained.
That is, When multiple keywords are to be sorted multiple times, a stable algorithm must be used

def bubble_sort(alist): """ 冒泡排序 """ if len(alist) <= 1: return alist for j in range(len(alist)-1,0,-1): for i in range(j): if alist[i] > alist[i+1]: alist[i], alist[i+1] = alist[i+1], alist[i] return alist
Optimal time complexity: \(O(n)\) Traversal does not find any elements that can be exchanged, and sorting ends
Worst time complexity: \(O(n^2)\)

def insert_sort(alist): """ 插入排序 """ n = len(alist) if n <= 1: return alist # 从第二个位置,即下表为1的元素开始向前插入 for i in range(1, n): j = i # 向前向前比较,如果小于前一个元素,交换两个元素 while alist[j] < alist[j-1] and j > 0: alist[j], alist[j-1] = alist[j-1], alist[j] j-=1 return alistComplexity and Stability
increment, and sorts each group using the direct insertion sorting algorithm; as the increment gradually decreases, each group contains more and more keywords. When the amount is reduced to 1, the entire file is divided into one group, and the algorithm terminates.
def shell_sort(alist): n = len(alist) gap = n//2 # gap 变化到0之前,插入算法之行的次数 while gap > 0: # 希尔排序, 与普通的插入算法的区别就是gap步长 for i in range(gap,n): j = i while alist[j] < alist[j-gap] and j > 0: alist[j], alist[j-gap] = alist[j-gap], alist[j] j-=gap gap = gap//2 return alistComplexity and Stability
The steps are:
Comparison of efficiency of common sorting algorithms
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