Detailed explanation of decimal to binary, hexadecimal and octal conversion in C#

1. Convert decimal to binary

Continuously divide the decimal number by 2 and fill in all the remainders backwards to get the required binary data.

        public static string DecimalToBinary(int vDecimal)
        {/* 将十进制的数 vDecimal 不断地除 2，取余数
             * 然后将余数 倒序 填写             */List<int> vYuShu = new List<int>();  // 除 2 过程中产生的余数集int vTempValue= vDecimal;            // 除 2 过程中产生的商数for (; ; )
            {int tempYS = vTempValue % 2;
                vYuShu.Add(tempYS);  // 记住余数vTempValue = vTempValue / 2;if (vTempValue == 0)  // 商数等于0时，结束运算break;
            }// 倒序输出string strBinary = "";for (int i = vYuShu.Count - 1; i >= 0; i--)
            {
                strBinary += vYuShu[i];
            }

            Console.WriteLine("Input decimal value:{0}, output binary value:{1}.", vDecimal, strBinary);return strBinary;
        }

##2. Convert binary to decimal

Multiply the value (0 or 1) in each binary digit by 2 raised to the (n-1) power, and convert each bit The results are added. Among them, n represents the number of digits from right to left in binary (counting from 1);

        public static int BinaryToDecimal(string vBinary)
        {// 首先判断是否满足输入要求int[] vInput = new int[vBinary.Length];for (int i = 0; i < vBinary.Length; i++)
            {var tempNum = vBinary[i].ToString();if (tempNum == "0")
                {
                    vInput[i] = 0;
                }else if (tempNum == "1")
                {
                    vInput[i] = 1;
                }else{throw new Exception("输入参数不正确，二进制数应仅由：0和1组成");
                }
            }/* 
             * 依次乘2的（n-1）次方，再求和             */int vDecimal = 0;for (int i = 1; i <= vInput.Length; i++)
            {
                vDecimal += (int)(Math.Pow(2, i - 1) * vInput[vInput.Length-i]);
            }

            Console.WriteLine("Input binary value:{0}, output decimal value:{1}.", vBinary, vDecimal);return vDecimal;
        }

3. Built-in conversion method

C#.Net’s built-in base conversion method:

            int vDecimal = 99;// 【10】 → 【2】string vBinary = Convert.ToString(vDecimal, 2);
            Console.WriteLine("十进制数:{0},转换成二进制:{1}", vDecimal, vBinary);// 【2】 → 【10】int tempDecimal = Convert.ToInt32(vBinary, 2);
            Console.WriteLine("二进制数:{0},转换成十进制:{1}", vBinary, tempDecimal);

#4. Decimal <=> Hexadecimal

            int vDecimal = 127;// 【10】 → 【16】string vStrHex = "0x" + Convert.ToString(vDecimal, 16);
            Console.WriteLine("十进制数:{0},转换成十六进制:{1}", vDecimal, vStrHex);// 【16】 → 【10】int tempDecimal = Convert.ToInt32(vStrHex, 16);
            Console.WriteLine("十六进制数:{0},转换成十进制:{1}", vStrHex, tempDecimal);

## Or you can:

##5. Decimal<=> Octal

##6. Other conversions

7. Signed number binary conversion

For data with positive and negative signs, the conversion is slightly different from the appeal.

1 byte (8 bits) can only represent 256 numbers anyway. Because it is signed, we express it as a range: -128 → 127.

Use the highest bit to represent the sign bit, 0 represents a positive number, and 1 represents a negative number.

10000000 represents the smallest negative integer in the computer. From 10000001 to 11111111, it means -127 to -1.

Negative integers are stored in two's complement form in computers.

        public static int BinaryToDecimalWithSign(string vBinary)
        {// 首先判断是否满足输入要求int[] vInput = new int[vBinary.Length];for (int i = 0; i < vBinary.Length; i++)
            {var tempNum = vBinary[i].ToString();if (tempNum == "0")
                {
                    vInput[i] = 0;
                }else if (tempNum == "1")
                {
                    vInput[i] = 1;
                }else{throw new Exception("输入参数不正确，二进制数应仅由：0和1组成");
                }
            }// -------- 不足8bits，补足 --------(非必需)if (vInput.Length % 8 != 0) // 补足8b、16b、、、            {int nLen = (vInput.Length / 8 + 1) * 8;int[] nInput = new int[nLen];for (int i = 0; i < nLen - vInput.Length; i++)
                {
                    nInput[i] = vInput[0];
                }
                vInput.CopyTo(nInput, nLen - vInput.Length);

                vInput = nInput;
            }// ---------------------------------// 第1步：首位为1，则为负值int vFH = vInput[0];if (vFH == 1)
            {// ---------- 第2步：减去一 ----------for (int i = 1; i <= vInput.Length; i++)
                {if (vInput[vInput.Length - i] == 1)
                    {
                        vInput[vInput.Length - i] = 0;break;
                    }else{
                        vInput[vInput.Length - i] = 1;
                    }
                }// ---------- 第3步：取反 ----------for (int i = 0; i < vInput.Length; i++)
                {
                    vInput[i] = 1 - vInput[i];
                }
            }// ---------- 第4步：转成10进制数 ----------int vDecimal = 0;for (int i = 1; i <= vInput.Length; i++)
            {
                vDecimal += (int)(Math.Pow(2, i - 1) * vInput[vInput.Length - i]);
            }if (vFH == 1) // 为负数            {
                vDecimal = 0 - vDecimal;
            }

            Console.WriteLine("Input binary value:{0}, output decimal value:{1}.", vBinary, vDecimal);return vDecimal;
        }

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