Home >Java >javaTutorial >Java Example - Find specified element in array
The following example demonstrates how to use the contains () method to find the specified element in the array:
/* author by w3cschool.cc 文件名:Main.java */import java.util.ArrayList;public class Main { public static void main(String[] args) { ArrayList objArray = new ArrayList(); ArrayList objArray2 = new ArrayList(); objArray2.add(0,"common1"); objArray2.add(1,"common2"); objArray2.add(2,"notcommon"); objArray2.add(3,"notcommon1"); objArray.add(0,"common1"); objArray.add(1,"common2"); System.out.println("objArray 的数组元素:"+objArray); System.out.println("objArray2 的数组元素:"+objArray2); System.out.println("objArray 是否包含字符串common2? : " +objArray.contains("common1")); System.out.println("objArray2 是否包含数组 objArray? :" +objArray2.contains(objArray) ); }}
The output result of running the above code is:
objArray 的数组元素:[common1, common2] objArray2 的数组元素:[common1, common2, notcommon, notcommon1] objArray 是否包含字符串common2? : true objArray2 是否包含数组 objArray? :false
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