When deleting LIST in java, list.remove(o) is generally used; but this often causes problems. Let’s look at the following code first:
package com.demo; import java.util.ArrayList; import java.util.List; public class Test11 { public void delete(){ List<Integer> list = new ArrayList<Integer>(); list.add(1); list.add(2); list.add(2); list.add(3); for (int i = 0; i < list.size(); i++) { if(list.get(i)==2){ list.remove(i); } } this.outputList(list); } private void outputList(List<Integer> list){ for (Integer i : list) { System.out.println(i); } } public static void main(String[] args) { Test11 t = new Test11(); t.delete(); } }
The return result is:
1 2 3
This result is obviously not what we expected. We wanted to delete all elements with an index of 2 in the List, but 2 appeared in the output result. This is because when i equals 1, element 2 with index 1 in the List was deleted. , at this time the list is [1,2,3], but then, after i is incremented, it is equal to 2. When list.get(i), the result taken out becomes 3, which means that as the list elements When deleting, the index will change accordingly. This is the trap. Therefore, we have to find an iterative method to delete that does not change the index when deleting. After the iterator is created, a single pointer to the original object will be created. Linked index table, when the original number of objects changes, the contents of this index table will not change synchronously, that is, cursor is used to maintain this index table, so it can be deleted like this:
package com.demo; import java.util.ArrayList; import java.util.Iterator; import java.util.List; public class Test11 { public void delete(){ List<Integer> list = new ArrayList<Integer>(); list.add(1); list.add(2); list.add(2); list.add(3); this.iteratorDelete(list.iterator(), 2); this.outputList(list); } private void iteratorDelete(Iterator<Integer> it, int deleteObject){ while(it.hasNext()){ int i = it.next(); if(i==deleteObject){ it.remove(); } } } private void outputList(List<Integer> list){ for (Integer i : list) { System.out.println(i); } } public static void main(String[] args) { Test11 t = new Test11(); t.delete(); } }
This code result That’s right!
Some people may say, I deleted it in the iterator, why did the value of the list change? Think about this issue yourself! If you can’t figure it out, you can change careers!
Summary
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