Home >Web Front-end >JS Tutorial >Detailed explanation of how to use JavaScript slice()

Detailed explanation of how to use JavaScript slice()

高洛峰
高洛峰Original
2016-11-28 13:56:191666browse

Definition and usage

slice() method returns selected elements from an existing array.

Syntax
arrayObject.slice(start,end)

Parameters

Description

start Required. Specifies where to start the selection. If negative, it specifies the position from the end of the array. That is, -1 refers to the last element, -2 refers to the second to last element, and so on.

end Optional. Specifies where the selection ends. This parameter is the array index at the end of the array fragment. If this parameter is not specified, the split array contains all elements from start to the end of the array. If this parameter is negative, it specifies the elements starting from the end of the array.

Return Value

Returns a new array containing the elements in arrayObject from start to end (excluding this element).

Description

Please note that this method does not modify the array, but returns a subarray. If you want to delete a segment of elements from an array, you should use the method Array.splice().

Tips and Notes

Note: You can use negative values ​​to select elements from the tail of an array.

Note: If end is not specified, the slice() method will select all elements from start to the end of the array.

Example Example 1

In this example, we will create a new array and then display the elements selected from it:




Output:


George,John,Thomas
John,Thomas
George, John, Thomas

Example 2

In this example, we will create a new array and then display the elements selected from it:




Output:


George,John,Thomas,James,Adrew,Martin
Thomas,James
George,John,Thomas,James,Adrew,Martin

TIY

slice()

How to use slice() to display selected elements from an existing array.


Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn