Matching of two strings in JavaScript

I encountered a problem at work. Two strings are matched. The requirement is: each string contains at most one *, ? can be unlimited

* represents a string of any length, and ? represents one character

The request can prompt two conflicts

< ;input type="button" onclick="checkMarchX()" value="CHECK">
Use Javascript to implement the code as follows:

[javascript]
function checkMarchX()
                                                                                                                                            Of(' *');
var str2XPosition = str2.indexOf('*');
var position = str1XPosition>str 2XPosition?str2XPosition ; (0,position);
                                                                                                           ))
                                                                                                    ​var str1XBackPosition = str1.length-str1XPosition-1;
          var str2XBackPosition = str2. length-str2XPosition-1;
                 var backposition = str1XBackPosition>str2XBackPosition?str2XBackPosition:str1XBackPosition;                                                                                                                         PatbackStr1 = str1.substring (Str1.length-Backposition, Str1.length);
VAR PATBACKSTR2 = Str2.Substring (str2.length-backposition, str2.length); C If (CheckMarchq (PatBackstr1, PatBackstr2))
{
Alert (str1+' and '+str2+"conflict");
                                                                                                                                         //alert(str1+'与'+str2+"前半部分冲突"); 
                var str1XBackPosition = str1.length-str1XPosition-1; 
                var str2XBackPosition = str2.length-str2XPosition-1; 
                var backposition = str1XBackPosition>str2XBackPosition?str2XBackPosition:str1XBackPosition; 
                if (backposition==0) 
                { 
                    alert(str1+'与'+str2+"冲突"); 
                } 
                else 
                { 
                    var patbackStr1 = str1.substring(str1.length-backposition,str1.length); 
                    var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                    if(checkMarchQ(patbackStr1,patbackStr2)) 
                    { 
                        alert(str1+'与'+str2+"冲突"); 
                    } 
                } 
            } 
        } 
        else if((str1XPosition==-1 && str2XPosition!=-1)||(str1XPosition!=-1 && str2XPosition==-1))//有且只有一个字符串含有* 
        { 
            var strX = str1XPosition==-1?str2:str1;//含有*的字符串 
            var strNoX = str1XPosition==-1?str1:str2;//不含*的字符串 
            if (strX.length-1            { 
                var position = strX.indexOf('*'); 
                if(position==0) 
                { 
                    //alert(str1+'与'+str2+"前半部分冲突"); 
                    var backposition = strX.length-position-1; 
                    if (backposition==0) 
                    { 
                        alert(str1+'与'+str2+"冲突"); 
                    } 
                    else 
                    { 
                        var patbackStr1 = str1.substring(str1.length-backposition,str1.length); 
                        var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                        if(checkMarchQ(patbackStr1,patbackStr2)) 
                        { 
                            alert(str1+'与'+str2+"冲突"); 
                        } 
                    } 
                } 
                else 
                { 
                    var patbeforeStr1 = str1.substring(0,position); 
                    var patbeforeStr2 = str2.substring(0,position); 
                    if(checkMarchQ(patbeforeStr1,patbeforeStr2)) 
                    { 
                        //alert(str1+'与'+str2+"前半部分冲突"); 
                        var backposition = strX.length-position-1; 
                        if (backposition==0) 
                        { 
                            alert(str1+'与'+str2+"冲突"); 
                        } 
                        else 
                        { 
                            var patbackStr1 = str1.substring(str1.length-backposition,str1.length); 
                            var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                            if(checkMarchQ(patbackStr1,patbackStr2)) 
                            { 
                                alert(str1+'与'+str2+"冲突"); 
                            } 
}
                                                                                                         if(checkMarchQ(str1,str2))
                                                                                                                                                                                                                    ​(str1 , str2)
{
var flagque = false;
if (str1.length == str2.length) {
// The same length can be conflicted
for (var I = 0; str1.Length; i ++)
                                                                                                                str(i,1)!=str2. substr(i,1))
                                                                                                                                  }                                                                                                                                                                                                                                                                                                                                              }

The * is at least one character. The above program does not verify the legality of the input