Asking God for guidance on arrays

I just want to take out the keys service_id, service_name, service_price, ipad_img, cart_id and their corresponding values. What should I do?

Reply content:

I just want to take out the keys service_id, service_name, service_price, ipad_img, cart_id and their corresponding values. What should I do?

To be simple and crude, please refer to the following

<code>$newArray = [];
foreach($array as $key=>$val){
  $newArray[$key]['service_id'] = $val['id']['service_id'];
  $newArray[$key]['service_name'] = $val['detail'][0]['service_name'];
  $newArray[$key]['service_price'] = $val['detail'][0]['service_price'];
  $newArray[$key]['ipad_img'] = $val['detail'][0]['ipad_img'];
  $newArray[$key]['cart_id'] = $val['cart_id']['cart_id'];
}
var_dump($newArray);</code>

Can you post the code on this picture so that I can run it? . .

$new_arr = [];
array_walk_recursive($arr, function($item, $key) use (&$new_arr) {
    $new_arr[$key] = $item;
});
print_r($new_arr);

Could you please tell me whether there is only one piece of data taken out from the database or multiple pieces?
Multiple items can be as follows:
$arr=[];
foreach($fruits as $k=>$v){

<code>$arr[$k]['service_id'] = $v['id']['service_id'];
$arr[$k]['service_name'] = $v['detail'][0]['service_name'];
$arr[$k]['service_price'] = $v['detail'][0]['service_price'];
$arr[$k]['ipad_img'] = $v['detail'][0]['ipad_img'];
$arr[$k]['cart_id'] = $v['cart_id']['cart_id'];</code>

}
print_R($arr);
If you want one, you can use the one upstairs

You can use left join;
Your table structure should be:
yld_cart:

cart_id	service_id	associator_id

yld_service:

service_id	service_name	service_price	ipag_img

The sql statement can be written like this:

SELECT cart_id , cart.`service_id` ,service.`service_name`,service.`service_price`,service.`ipad_img`FROM `yjd_cart` as cart LEFT JOIN `yjd_service` service ON cart.service_id = service.service_id WHERE cart.associator_id=1

yii2 can be written like this:

$query = new Query();
        $associator_id = 1;
        $result = $query->select(['cart_id','yjd_cart.service_id','yjd_service.service_name','yjd_service.service_price','yjd_service.ipad_img'])
            ->from('yjd_cart')
            ->leftJoin('yjd_service','yjd_service.service_id = yjd_cart.service_id')
            ->where(['yjd_cart.associator_id'=>$associator_id])
            ->all();

        var_dump($result);