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一个PHP的远程图片抓取函数分享_php技巧

WBOY
WBOYOriginal
2016-05-17 08:55:16845browse
复制代码 代码如下:

function grabImage($url, $filename = '') {
if($url == '') {
return false; //如果 $url 为空则返回 false;
}
$ext_name = strrchr($url, '.'); //获取图片的扩展名
if($ext_name != '.gif' && $ext_name != '.jpg' && $ext_name != '.bmp' && $ext_name != '.png') {
return false; //格式不在允许的范围
}
if($filename == '') {
$filename = time().$ext_name; //以时间戳另起名
}
//开始捕获
ob_start();
readfile($url);
$img_data = ob_get_contents();
ob_end_clean();
$size = strlen($img_data);
$local_file = fopen($filename , 'a');
fwrite($local_file, $img_data);
fclose($local_file);
return $filename;
}
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