javascript - next quotation mark problem after php regular match

<code>$html = <<<EOF
<a href="a.php?u=ABjhpIVC;b=5" onmousedown="return rwt(AFQjCNH3RnE94GMEJkoxp0Iy1fSbpjbbwQ)">title</a>
EOF;

$isMatched = preg_match('/<a(.*?)href="(.*?)">(.*?)<\/a>/', $html, $matches);</code>

I used this code to finally match the content from to
">title
The final output result
a.php?u=ABjhpIVC;b=5" onmousedown="return rwt (AFQjCNH3RnE94GMEJkoxp0Iy1fSbpjbbwQ)
I want to get the content between the first double quotation mark and the second quotation mark, which is the content of the a tag href=
I don’t need to get the content from the first quotation mark to the last double quotation mark, please ask How can I modify this code to match it?

Reply content:

<code>$html = <<<EOF
<a href="a.php?u=ABjhpIVC;b=5" onmousedown="return rwt(AFQjCNH3RnE94GMEJkoxp0Iy1fSbpjbbwQ)">title</a>
EOF;

$isMatched = preg_match('/<a(.*?)href="(.*?)">(.*?)<\/a>/', $html, $matches);</code>

I used this code to finally match the content from to
">title
The final output result
a.php?u=ABjhpIVC;b=5" onmousedown="return rwt (AFQjCNH3RnE94GMEJkoxp0Iy1fSbpjbbwQ)
I want to get the content between the first double quotation mark and the second quotation mark, which is the content of the a tag href=
I don’t need to get the content from the first quotation mark to the last double quotation mark, please ask How can I modify this code to match it?

Then you have to use greedy matching~
/<a(.*?)href="(.*)">(.*?)</a>/
You use .*? is followed by " and he will stop as long as he matches the next character "

Using forbidden greedy matching U
Personal experience, when you write the regular expression, always add Uis

'/(.*)/iU', there are attributes after href, don’t write the ones that can’t be matched