PHP+JS three-level menu linkage menu implementation method

The example in this article describes the implementation method of PHP+JS three-level menu linkage menu. Share it with everyone for your reference, the details are as follows:

  
    <title>
      智能递归菜单-读取数据库
    </title>
    <style>
      TD { FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; LINE-HEIGHT: 130%;
      letter-spacing:1px } A:link { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体";
      FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:visited
      { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
      none; letter-spacing:1px } A:active { COLOR: #990000; FONT-FAMILY: "Verdana",
      "宋体"; FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:hover
      { COLOR: #ff0000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
      underline; letter-spacing:1px } .Menu { COLOR:#000000; FONT-FAMILY: "Verdana",
      "宋体"; FONT-SIZE: 12px; CURSOR: hand }
    </style>
    <script language="javascript">
      function ShowMenu(MenuID) {
        if (MenuID.style.display == "none") {
          MenuID.style.display = "";
        } else {
          MenuID.style.display = "none";
        }
      }
    </script>
  
  
0) ShowTreeMenu($Con, $result, $layer, $ID); 
//=============================================
//显示树型菜单函数 ShowTreeMenu($con,$result,$layer) //$con：数据库连接 
//$result：需要显示的菜单记录集
//layer：需要显示的菜单的级数 
//=============================================
function
ShowTreeMenu($Con, $result, $layer) {
//取得需要显示的菜单的项目数
$numrows=mysql_num_rows($result);
  //开始显示菜单，每个子菜单都用一个表格来表示 echo "
    "; for($rows=0;$rows
         "; //如果该菜单项目有子菜单，则添加JavaScript onClick语句 if(mysql_num_rows($result_sub)>
          0) { echo "    "; echo "  "; } else { echo "    "; echo "  "; } //如果该菜单项目没有子菜单，并指定了超级连接地址，则指定为超级连接， //否则只显示菜单名称 if($menu[url]!="")
              echo "  $menu[name]  "; else echo $menu[name]; echo "   "; //如果该菜单项目有子菜单，则显示子菜单 if(mysql_num_rows($result_sub)>0) { //指定该子菜单的ID和style，以便和onClick语句相对应
            echo " ";
  echo "<td width="20"></td>";
  echo "<td>";
  //将级数加1
  $layer++;
  //递归调用ShowTreeMenu()函数，生成子菜单 
  ShowTreeMenu($Con,$result_sub,$layer);
  //子菜单处理完成，返回到递归的上一层，将级数减1
  $layer--;
  echo "  ";
  }
  //继续显示下一个菜单项目
  } echo "  "; }
  ?>
       ".($id). "  ";
      // 在 PHP 4 中这里会打印出 1
      ?>
       ".$b. "  ";
      ?>
  


<p>Readers who are interested in more PHP-related content can check out the special topics of this site: "Introduction Tutorial on PHP Object-Oriented Programming", "Summary of PHP String Usage" ", "Introduction Tutorial on PHP+MySQL Database Operation" and "Summary of Common PHP Database Operation Skills"</p>
<p>I hope this article will be helpful to everyone in PHP programming. </p>
                
                
                <p>
                    The above introduces the implementation method of PHP+JS three-level menu linkage menu, including the relevant content. I hope it will be helpful to friends who are interested in PHP tutorials. </p>
                <p>
                    </p>
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