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PHP query voting exercise (0508)
- WBOYOriginal
- 2016-07-29 08:50:411000browse
Practice questions:
Solution:
Method 1:
1. Main voting page:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" c />
<title>投票</title>
<style>
#list
{
width:400px;
height:300px;}
#jieguo
{
width:400px;
height:300px;}
.x
{
float:left;}
</style>
</head>
<body>
<form action="TouChuLi.php" method="post">
<?php
include ("DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div>";
foreach ($arrxx as $v)
{
echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
?>
<input type="submit" value="提交">
<input type="button" value="查看结果" >
<?php
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$zrs=$db->query($sqlzs);
foreach ($arrxx as $v)
{
$name=$v[1];
$number=$v[2];
if($zrs[0][0]==0)
{
$bfb = 0;
}
else
{
$bfb = ($number/$zrs[0][0])*100;
}
$bfb=round($bfb,2);
echo "<div>
<span>{$name} </span>
<div >
<div> </div>
</div>
<span>{$number} </span>
<span>{$bfb}% </span>
</div>
<br />
";
}
?>
<input type="button" value="返回" ><pre class="brush:php;toolbar:false"><?php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
foreach($arr as $v)
{
$sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
$db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
?>
3. Establish access database Class, encapsulation for reference:
<?php
//执行一个sql语句，返回相应的结果
class DBDA
{
public $host="localhost";//数据库服务器地址
public $uid="root";//数据库用户名
public $password="";//数据库密码
//执行SQL语句的方法
//参数里面：$sql代表要执行的sql语句；$type是sql语句的类型，0代表查询，1代表其他(增删改)；$db代表要操作的数据库
function Query($sql,$type=0,$db="mydb")
{
//造连接对象
$dbc MySQLi($this->host,$this->uid,$this->password,$db);
//判断连接是否出错
!mysqli_connect_error() or die("连接失败！");
//执行sql语句
$result=$dbconnect->query($sql);
//判断SQL语句类型
if($type==0)
{
//如果是查询语句返回结果集的二维数组
return $result->fetch_all();
}
else
{
//如果是其他语句，返回true或false
return $result;
}
}
}
Method 2:
1. Voting main page:
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" c />
<title>投票</title>
<style>
.x
{
float:left;}
</style>
</head>
<body>
<form action="TouChuLi.php" method="post">
<?php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div>";
foreach ($arrxx as $v)
{
echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
?>
<input type="submit" value="提交">
<a href="ChaKan.php"><input type="button" value="查看结果" ></a>
</form>
</body>
</html>
2. Processing voting page:
<?php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
foreach($arr as $v)
{
$sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
$db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
?>
3. View voting results page:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" c />
<title>查看结果</title>
<style>
.x
{
float:left;}
</style>
</head>
<body>
<?php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$arrxx=$db->query($sqlxx);
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$zrs=$db->query($sqlzs);
foreach ($arrxx as $v)
{
$name=$v[1];//调研项目名称
$number=$v[2];//选择该项的人数
//判断总人数是否为0
if($zrs[0][0]==0)
{
$bfb = 0;
}
else
{
$bfb = ($number/$zrs[0][0])*100;//求百分比
}
$bfb=round($bfb,2); //取小数点后两位
echo "<div>
<span>{$name} </span>
<div >
<div> </div>
</div>
<span>{$number} </span>
<span>{$bfb}%</span><br />
</div><br />";
}
?>
<br />
<a href="TouPiao.php"><input type="button" value="返回"></a>
</body>
</html>
Web page display results:
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