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HomeBackend DevelopmentPHP TutorialPHP Parse Error: syntax error, unexpected $end error solution

Configure the server. When accessing php, it prompts PHP Parse Error: syntax error, unexpected $end error. Share my solution.

When writing PHP programs these days, I feel that many aspects are not as smooth as ASP, ASP.NET, and JSP. For example, using session_first-come-first-server session_start(); and using file jump headers are not convenient....

Maybe it’s some features of PHP that I’m not familiar with, but as I write more, I’ll gradually get used to it...

Complete a code writing and debugging problem, the error is as follows: Parse error: syntax error, unexpected $end in D:xampphtdocsguestBookguestBook.php on line 330

Look at line 330 of the program, the last line of code. What’s wrong with this? Searched on google and found: In PHP 5, the following error may appear as an error entry in Apache error log or simply displays on PHP web page, even if calling to php scripts with php_info() works perfectly and successfully returns information on PHP configurations:

Parse Error: syntax error, unexpected $end in ….. scripts.php on line …

The error may caused by a missing curly bracket in PHP script coding. Besides, it may also caused by error in PHP coding in class definition, as in PHP, a class definition cannot be broke up and distributed into multiple files, or into multiple PHP blocks, unless the break is within a method declaration.

But more commonly, the error is often caused by the use of Short Open tags in PHP,

To use short open tags, it must be enabled in PHP.INI. Search for short_open_tag in PHP.INI, and change the value to On. The line should look line:

short_open_tag = On

roughly meaning: The error occurs because short tags are used. You can set short_open_tag = On in php.ini

It turns out that Parse error prompts are usually grammatical errors, using open tags, and not ending the statement, which are some basic programming mistakes, such as not paying attention to adding ";" at the end of the statement or forgetting "} after if(){...} ";forgot"?>". Checking the code carefully, it turns out that "}" is missing somewhere, and the modified program runs normally.



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