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mysql+php paging class (tested)_PHP tutorial

Jul 21, 2016 pm 03:53 PM
mysqlphpcodePaginationparametercopykind

Copy code The code is as follows:

/*     
mysql_pager.class.php     

三个参数。 mysql_query()的结果, url变量page, 您要的每页记录数     
例子在这个文件底部     
淡水河边整理测试     
*/      

class mysql_pager {      
  // define properties      
  var $page;      
  var $result;      
  var $results_per_page = 3;      
  var $total_pages;        

/*       
Define the methods     

  下面是构造函数,和类同名(>php4)     
   需要查询的结果句柄,当前页码,每页记录数     
   like:  $f->mysql_pager($result, 1, 15);     
*/      

function mysql_pager( $result, $current_page, $results_per_page ) {      

    if(!$result){      
        echo "
数据库未运行,结果集错误
\n";        
        return;      
        }      

   $this->result = $result;      

   if(!$current_page || $current_page         $this->page = 1;      
   else $this->page = $current_page;      

   if(!emptyempty($results_per_page))        
      $this->results_per_page = $results_per_page;      

   $numrows = @mysql_num_rows($this->result);        
   if(!$numrows) {      
      echo "
查询结果为空.
n";
return;
}

$this->total_pages = ceil($numrows / $this->results_per_page);                                                                                     * The following is a function of the print content. n";
$start = ($this->page - 1) * $this->results_per_page; start);
$x = 0; {                                                                                                                                                                                                                                 $bgcolor =$bgcolor>
";                                                        🎜> echo "
n";
}

/*                                                                                                                                                                                $PHP_SELF;

echo "
";

for($i = 1; $i total_pages; $i++) { # loop to print >
if($i == 1 && $this->page > 1) #Prints the echo "page - 1)."" onMouseOver="status="Previous Page"; return true;" onMouseOut="status=" ";return true;">?"; a link itself, just prints page number
echo " $i ";

if($i != $this-> page) #Other links that aren"t this page go here
echo " $i ";

if($i == $this->total_pages && $this->page != $ this->total_pages) # Link for next page >> (not on last page)
echo "page + 1). "" onMouseOver="status="Go to the Next Page";return true;" onMouseOut="status=" ";return true;">?"; > echo "
n"; "
} "

} " > mysql_select_db( "$db");
$result= @mysql_query("Select * FROM table");

$p = new mysql_pager( $result, $page=$_GET["page"], 10 );
$p->print_navigation();
$p->print_paged_results(); ;

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/318727.htmlTechArticleCopy the code as follows: ?php /* mysql_pager.class.php Three parameters. The result of mysql_query(), the url variable page, the number of records per page you want. The example is at the bottom of this file. Tamsui Riverside finishing test...
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