PHP email mailbox regular_PHP tutorial

1. Verify email:

Copy code The code is as follows:

1. 2. if ( ereg(“/^[a-z]([a-z0-9]*[-_.]?[a-z0-9]+)*@([a-z0-9]*[-_]?[a -z0-9]+)+[.][a-z]{2,3}([.][a-z]{2})?$/i; ”,$email)){
3. echo “Your email address is correct!";}
4. else{
5. echo "Please try again!";
6. }
7. ?>

The format of the international domain name is as follows:
The domain name is composed of any combination of specific character sets, English letters, numbers and "-" (i.e. hyphens or minus signs) in various countries, but it cannot contain "-" at the beginning or at the end. "-" cannot appear continuously. Letters in domain names are not case-sensitive. The domain name can be up to 60 bytes long (including suffixes .com, .net, .org, etc.).
/^[a-z]([a-z0-9]*[-_]?[a-z0-9]+)*@([a-z0-9]*[-_]?[a- z0-9]+)+[.][a-z]{2,3}([.][a-z]{2})?$/i;
/content/i forms a case-insensitive regular expression Formula;
^ Match start
$ Match end
[a-z] E-Mail prefix must start with an English letter
([a-z0-9]*[-_]?[a- z0-9]+)* matches _a_2, aaa11, _1_a_2, but does not match a1_, aaff_33a_, a__aa. If it is a null character, it will also match. * means 0 or more.
* represents 0 or more previous characters.
[a-z0-9]* matches 0 or more English letters or numbers
[-_]? matches 0 or 1 "- ", because "-" cannot appear continuously
[a-z0-9]+ matches one or more English letters or numbers, because "-" cannot be the end
@ There must be @
([a-z0-9]*[-_]?[a-z0-9]+)+ see above ([a-z0-9]*[-_]?[a-z0-9]+) *Explanation, but it cannot be empty, + means one or more.
[.] Treat special characters (.) as ordinary characters
[a-z]{2,3} matches 2 to 3 English letters, usually com or net, etc.
([.][ a-z]{2})? Match 0 or 1 [.][a-z]{2} (such as .cn, etc.) I don’t know if the last part of .com.cn is usually two digits. If not, please Modify {2} to {starting word count, ending word count}
Perfect E-Mail regular expression, with detailed explanation, please help test it! 2. Extract email from the string:
function getEmail($str) {
$pattern = "/([a-z0-9]*[-_.]?[ a-z0-9]+)*@([a-z0-9]*[-_]?[a-z0-9]+)+[.][a-z]{2,3}([.][ a-z]{2})?/i";
preg_match_all($pattern,$str,$emailArr);
return $emailArr[0];
}
$emailstr = "9999@qq .com.cn If I am not from Mivi, I will open an iid mailing list: fuyongjie@163.com and hh@qq.com;, fuyongjie.100@yahoo.com, fu-1999@sina.com";
$emailArr = getEmail($emailstr);
echo "

"; <br>print_r($emailArr); <br>echo "

";
?>
Print as follows:
Array
(
[0] => 9999@qq.com.cn
[1] => fuyongjie@163.com
[2] => ; hh@qq.com
[3] => fuyongjie.100@yahoo.com
[4] => fu-1999@sina.com
)
3. Comparison: No. The regular expression in 2 no longer contains the first ^ and $;

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