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Solution to Cannot use a scalar value as an array under PHP_PHP Tutorial
- WBOYOriginal
- 2016-07-21 15:34:351443browse
Today when I was testing a php program, an error message appeared: Cannot use a scalar value as an array. This error message also appeared a few days ago. At that time, it seemed that it would be fine if I adjusted it a little. I didn't go into it deeply, but today it happened again. appeared.
I can’t fool around anymore, I have to find out the reasons and solutions, so I searched and searched online, but I couldn’t find the result after searching for a long time. It’s not that such problems can’t be found online, but there are very few. Someone gave a positive and accurate answer. The last paragraph of this article made me suddenly understand what was going on.
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What needs to be noted is the type conversion:
If a variable name (such as a) has been defined as a non-array type, For example, integer, then a can be converted to floating point, string (even object type), but it cannot be an array, that is, a[0]=1; is wrong, and PHP will report such a warning "Cannot use a scalar" value as an array". Even if a is defined as a one-dimensional array, it cannot be converted to a high-dimensional array.
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The following are solutions to the problems found by other netizens:
After seeing this sentence, I carefully After checking the code, I found that a Boolean variable I had defined above was directly called as an array below, so an error occurred.
If a non-array element has been defined and assigned a value, and then used as an array, the error "Cannot use a scalar value as an array" will occur
For example: var $i=1000 ;
$i[5]=345; // An error will occur at this time,
So everyone should give up this non-standard way of writing code.