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PHP time and date operation practice_PHP tutorial

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WBOYOriginal
2016-07-21 15:25:33885browse

常见常用的时间函数:
1.time(); //取得1970/1/1 00:00:00 到现在的总秒数


2.mktime(); //设定时间


3.date(); //取得时间的详细资讯


代表字串 说明 范例 输出
年:
Y 西元年(4位) 2011
y 西元年(2位) 11
月:
m 月份,不足二位补零(01~12) 01
n 月份,不足二位不补零(1~12) 1
t 本月共有几天(1~31) 31
M 英文月份名(缩写) Jan
F 英文月份名(全名) January
日:
d 日期,不足二位补零(01~31) 01
j 日期,不足二位不补零(01~31) 1
星期:
w 数字型的星期,(以0~6代表一到日) 0
D 星期名(缩写) Sun
l 星期名(全名) Sunday
时:
H 24时制小时,不足二位补零(00~23) 07
G 24时制小时,不足二位不补零(0~23) 7
h 12时制小时,不足二位补零(01~12) 07
g 12时制小时,不足二位不补零(1~12) 7
分:
i 分钟,不足二位补零(00~59) 40
秒:
s 秒钟,不足二位补零(00~59) 45
S 秒钟,不足二位补零(00~59)加上英文顺序 45th
上下午:
A 大写AM/PM AM
a 小写am/pm am
其他:
U 1970/1/1 00:00:00 到指定天的总秒数 1156780800
z 一年当中的第几天(0~365) 255
*The red background represents frequently used parameters

Some common uses:
1. Get the total number of seconds from 0:00:00 on January 1, 1970 to today:
Copy code The code is as follows:

echo date("U",mktime(0,0,0 ,date("Y"),date("m"),date("d")));
?>

2. Get the total seconds from today to 7 days before and after Number:
Copy code The code is as follows:

$setTime = date("U",mktime (0,0,0,7,20,2011));
$time = date("U",mktime(0,0,0,date("m"),date("d"),date ("Y")));
$start = $time-86400*7;
$over = $time+86400*7;
if($start>=$time&&$time<=$ over)
{
echo "The specified time is within 7 days before and after today";
}
else
{
echo "The specified time has exceeded within 7 days before and after today";
}
?>

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/324112.htmlTechArticleCommonly used time functions: 1.time(); //Get 1970/1/1 00:00: 00 The total number of seconds to now?echo time();? 2.mktime(); //Set time?echo date("U",mktime(0,0,0,1,20,2011));/ /output19...
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