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Solution to PHP warning Cannot use a scalar value as an array_PHP Tutorial
- WBOYOriginal
- 2016-07-21 15:21:07955browse
I saw some prompts like this in the php error log:
[27-Aug-2011 22:26:12] PHP Warning: Cannot use a scalar value as an array in /www/hx/enjoy.php on line 14
[27-Aug-2011 22:26:18] PHP Warning: Cannot use a scalar value as an array in /www/hx/enjoy.php on line 14
Check source program , probably as follows:
Copy code The code is as follows:
$arr_hx = $mem->get(' hx');
if(!$arr_hx) {
$arr_hx['a'] = 'b';
$mem->set('hx',$arr_hx);
}
Basically understood, when $mem->get does not get a value, it returns false. At this time, $arr_hx is false, a Boolean value, and then it is used as an array, resulting in This prompt was generated. In fact, it is also a case where the variable is not defined. Add $arr_hx = array() before the assignment to solve the problem.
After checking, there is the following description:
Quotation
What needs to be noted is the type conversion:
If a variable name (such as a) has been defined as a non-array type, for example integer, then a can be converted to floating point, string (even object type), but it cannot be an array, that is, a[0]=1; is wrong, and PHP will issue such a warning "Cannot use a scalar value as an array". Even if a is defined as a one-dimensional array, it cannot be converted to a high-dimensional array.
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