


How to determine whether a web page request is an ajax request or a normal request in php? You can achieve this by passing parameters, for example, use the following URL request:
/path/to/pkphp.com/script.php?ajax
Use the following method to determine in the php script:
if(isset($_GET['ajax'])) {
...this is an ajax request, then...
}
else {
...this is not an ajax request, then...
}
Judgement of web page requests is simply implemented by passing the _GET parameter. However, if such a function is needed, this method may have drawbacks. The functional requirements are as follows:
1. The content of the web page requested through ajax is different from that of the ordinary requested web page
2. The web page requested through ajax is to facilitate user operation. The required content of the web page requested by the two methods is the same, but the content of the web page requested by ajax is relatively simplified and used, and the large frame template of the web page is removed.
3. The purpose of this is: when the user operates the web page through ajax, and when the search engine accesses the web page (equivalent to opening the web page normally), the content obtained is a complete web page (including the large frame template of the web page) ).
To complete the above function, you cannot use the GET parameter passing introduced earlier to judge. If you use GET passing to judge, the user ajax request and the ordinary web page request will have the same content, because you It is impossible to set a URL with and without ajax judgment parameters for a link. So how can we implement this function? This problem must be solved through server-side PHP judgment. That is, today I will talk about how PHP judges ajax requests. There is a prerequisite for solving this problem, that is, the ajax framework you use must be jquery. In the jquery framework, when requesting web content through its $.ajax, $.get, or $.post method, it will pass an HTTP_X_REQUESTED_WITH parameter to the server. You can use the following method to determine whether a request is an ajax request or an ajax request. Ordinary request:
if(isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower( $_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest')
{
..this is an ajax request, then...
}
else {
..this is not an ajax request ajax request, and then...
}
Using this to perform judgment operations can keep the URLs on the web page consistent, but you can get web pages with different content for two different requests. . It achieves user operation optimization without affecting search engine inclusion. I think it is a great solution!
There is another issue that needs attention here, that isIf your jquery request opens the web page through an iframe, then the HTTP_X_REQUESTED_WITH parameter will not be passed , which means you do not Method to determine the type of request.

php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

实现方法:1、使用“sleep(延迟秒数)”语句,可延迟执行函数若干秒;2、使用“time_nanosleep(延迟秒数,延迟纳秒数)”语句,可延迟执行函数若干秒和纳秒;3、使用“time_sleep_until(time()+7)”语句。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

php字符串有下标。在PHP中,下标不仅可以应用于数组和对象,还可应用于字符串,利用字符串的下标和中括号“[]”可以访问指定索引位置的字符,并对该字符进行读写,语法“字符串名[下标值]”;字符串的下标值(索引值)只能是整数类型,起始值为0。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。

方法:1、用“str_replace(" ","其他字符",$str)”语句,可将nbsp符替换为其他字符;2、用“preg_replace("/(\s|\ \;||\xc2\xa0)/","其他字符",$str)”语句。

查找方法:1、用strpos(),语法“strpos("字符串值","查找子串")+1”;2、用stripos(),语法“strpos("字符串值","查找子串")+1”。因为字符串是从0开始计数的,因此两个函数获取的位置需要进行加1处理。


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